Amines

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

1 . 8 6 9 3 = w 1 3 5

W = 2.70 g

Mass produced actual = 2.70 * 9 0 1 0 0 = 2 . 4 3 = 2 4 3 * 1 0 2 g

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Gabriel phthalimide synthesis is used for 1° Aliphatic /alicyclic amine

1° Amine

CH3 – CH2 – NH2

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5 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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5 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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P
Payal Gupta

Contributor-Level 10

Stable carbocation formation is the important factor.

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5 months ago

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P
Payal Gupta

Contributor-Level 10

Primary amine, whether aliphatic or aromatic when warmed with CHCl3, alcoholic (KOH) it forms isocyanide

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A
alok kumar singh

Contributor-Level 10

Mass of empty cylinder = 14.8 kg

Mass of cylinder when full = 29 kg

Mass of gas in cylinder when filled; W1 = 29 – 14.8 = 14.2 kg

Mass of gas in cylinder after using, W2 = 23 – 14.8 = 8.2 kg

Initial pressure ; P1 = 3.47 atm

Final pressure ; P2 =?

Using

  P V = W M R T

P 1 V = W 1 M R T . . . . . . . . . . ( I )              

P 2 V = W 2 M R T . . . . . . . . . . . ( I I )                 

P 1 P 2 = W 1 W 2                

3 . 4 7 P 2 = 1 4 . 2 8 . 2                

P2 = atm

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

C 2 H 7 N + ( 2 x + y 2 ) C u O x C O 2 + y 2 H 2 O + Z 2 N 2 + ( 2 x + y 2 ) C u

C 2 H 7 N 1 + ( 2 * 2 + 7 2 ) C u O 2 C O 2 + 7 2 H 2 O + 1 2 N 2 + ( 2 * 2 + 7 2 ) C u              

y = 7              

Ans. = 7

New answer posted

5 months ago

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R
Raj Pandey

Contributor-Level 9

Reagents can be used are Þ       (1) Sn/HCl

                                                                        (2) Fe/HCl

                       

...more

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Dumas method,

Moles of N in N, N-dimethylaminopentane (C7H17N)

= 5 7 . 5 1 1 5 = 0 . 5 m o l e

C 7 H 1 7 N + 4 5 2 C u O 7 C O 2 + 1 7 2 H 2 O + 1 2 N 2 + 4 5 2 C u

n C u O ( 4 5 2 ) = n c 7 H 1 7 N 1

n C u O = ( 4 5 2 ) * 0 . 5 m o l

= 11.25 mol

= 1125 * 10-2 mol

Ans. = 1125

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