Amines
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New answer posted
4 months agoContributor-Level 10
This is a Short Type Questions as classified in NCERT Exemplar
Ans:
New answer posted
4 months agoContributor-Level 10
This is a Short Type Questions as classified in NCERT Exemplar
Ans: CH3CH2CH3 < CH3CH2NH2 < CH3CH2OH
As oxygen is more electronegative than nitrogen therefore, the O-H bond is more polar than the N-H bond. So ethanol has more dipole moments than ethylamine. Propane is non- polar in nature hence, had the least among all.
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4 months agoContributor-Level 10
This is a Short Type Questions as classified in NCERT Exemplar
Ans: CS2 is a non-polar solvent which decreases the activating effect of? NH2. As a result, mono substitution occurs only at o- and p- positions giving a mixture of 2-bromoaniline (minor) and 4-bromoaniline (major) as products.
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4 months agoContributor-Level 10
This is a Short Type Questions as classified in NCERT Exemplar
Ans: The azo products have an extended conjugate system with both aromatic rings linked by the –N=N- bond. These compounds are frequently colored and used as dyes. Benzene diazonium chloride reacts with phenol to form p-hydroxy azobenzene by coupling the phenol molecule in its para position with the diazonium salt. This is referred to as a coupling reaction.
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4 months agoContributor-Level 10
This is a Short Type Questions as classified in NCERT Exemplar
Ans: Amides are the byproducts of the acylation reaction. The reaction is carried out in the presence of a stronger base than the amine, such as pyridine, which removes the formed HCl and shifts the equilibrium to the right.
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4 months agoContributor-Level 10
This is a Short Type Questions as classified in NCERT Exemplar
Ans: As the electronegativity of oxygen is more than the electronegativity of a nitrogen atom, the O−H bond is more polar than the N−H bond, therefore MeOH is stronger acid than MeNH2 or MeNH2 is stronger base than MeOH.
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4 months agoContributor-Level 10
This is a Short Type Questions as classified in NCERT Exemplar
Ans: As −NH2 is a strong activating group, the aniline will readily undergo electrophilic substitution reaction, and it is difficult to cease reaction at the mono substitution stage.
Therefore, the activating group −NH2 is protected by an acetylation process.
The acetylated complex formed utilizes the lone pair of nitrogen and are less available for donation, this helps to carry out the nitration reaction easily.
New answer posted
4 months agoContributor-Level 10
This is a Short Type Questions as classified in NCERT Exemplar
Ans: The reaction of aniline with nitrous acid at 273-278 K produces benzene diazonium chloride. The reaction of sodium nitrite with hydrochloric acid produces nitrous acid in the reaction mixture. Diazotisation is the process of converting primary aromatic amines into diazonium salts. Because of its instability, the diazonium salt is generally not stored or used immediately after preparation.
The crystalline solid benzene diazonium chloride is colorless.
It is easily soluble in water and stable at room temperature, but it reacts with water when warmed.
In the dry state, i
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4 months agoContributor-Level 10
This is a Short Type Questions as classified in NCERT Exemplar
Ans: Hinsberg's reagent is also known as benzenesulphonyl chloride (C6H5SO2Cl). When it reacts with primary and secondary amines, it produces sulphonamides. Allowing secondary and tertiary amines to react with Hinsberg's reagent allows them to be distinguished (benzenesulphonyl chloride C6H5SO2Cl). Secondary amines react with Hinsberg's reagent to form an alkali-insoluble product. N, N-diethylamine, for example, reacts with Hinsberg's reagent to form N, N-diethylbenzenesulphonamide, which is insoluble in alkalis. Tertiary amines, on the other hand, are unaffected by Hin
New answer posted
4 months ago
Contributor-Level 10
This is a Short Type Questions as classified in NCERT Exemplar
Ans:
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