Chemistry NCERT Exemplar Solutions Class 11th Chapter Eleven
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2 months agoContributor-Level 10
π = iCRT
P? = 1 * (10/180) * R * T (For Glucose)
P? = 1 * (10/60) * R * T (For Urea)
P? = 1 * (10/342) * R * T (For Sucrose)
∴ P? > P? > P?
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2 months ago
Contributor-Level 10
10amines react with Hingsberg's reagent to give a solid, which dissolve in alkali.
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2 months agoContributor-Level 10
The maximum temperature that can be achieved in blast furnace is upto 
.
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2 months agoContributor-Level 10
Λ°m (NaCl) = 126.45Scm² mol? ¹
Λ°m (HCl) = 426.16Scm² mol? ¹
Λ°m (CH? COONa) = 91Scm² mol? ¹
Λ°m (CH? COOH) =Λ°m (CH? COONa) +Λ°m (HCl)−Λ°m (NaCl)
= 91 + 426.16 – 126.45
= 391.72Scm² mol? ¹
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2 months ago
New answer posted
2 months agoContributor-Level 10
Vitamin B? deficiency → Pernicious anaemia (RBC deficient in heamoglobin)
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2 months agoNew answer posted
2 months ago
Contributor-Level 10
For a given reaction? H is negative. Hence, potential energy profile is of an exothermic reaction.
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2 months agoContributor-Level 10
Due to lanthanoid contraction Zr and Hf has similar atomic and ionic radii.
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2 months agoContributor-Level 10
No. of atoms in Hexagonal primitive unit cell = 6
No. of Tetrahedral voids = 2 * No. of atoms per unit cell
= 2 * 6 = 12
No. of Octahedral voids = No. of atoms per unit cell = 6
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