Chemistry NCERT Exemplar Solutions Class 11th Chapter Eleven
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New answer posted
2 months agoContributor-Level 10
ln K = ln A – (E? /R) (1/T)
In ln K v/s 1/T graph
Slope = –E? /R
–5 * 10³ = –E? /8.314
E? = 5 * 10³ * 8.314
= 41500 J mol? ¹ or 41.5 kJ mol? ¹
New answer posted
2 months agoContributor-Level 10
H? O < H? S < H? Se < H? Te
Down the group acidic strength increases
So pK? value decreases
New answer posted
2 months agoContributor-Level 10
For irreversible expansion of an ideal gas under isothermal condition
ΔU = 0, ΔS (Total) ≠ 0
New answer posted
2 months agoContributor-Level 10
n (B) = 3/2
n (B) = 3, n (O) = 2
n (Total) = 3 + 2 = 5
X (B) = n (B) / n (T) = 3/5
X (O) = n (O) / n (T) = 2/5
P (S) = P° (B)X (B) + P° (O)X (O)
P (S) = 280 * (3/5) + 420 * (2/5)
= 336 mm of Hg
New answer posted
2 months agoContributor-Level 10
n (O? ) = 4/32 = 1/8 mol
n (H? ) = 2/2 = 1 mol
n (Total) = n (O? ) + n (H? ) = 1/8 + 1 = 9/8 mol
PV = nRT
P (Total) * 1 = (9/8) * 0.082 * 273
P (Total) = 25.18 atm
New answer posted
2 months agoContributor-Level 10
Λ°? (CH? COOH) = Λ°? (H? ) + Λ°? (CH? COO? ) = 350 + 50 = 400Scm² mol? ¹
α = Λ? / Λ°?
α = 20/400 = 5 * 10? ²
K? (CH? COOH) = Cα²
= 0.007 * (5 * 10? ²)²
= 1.75 * 10? molL? ¹
New answer posted
2 months agoContributor-Level 10
Total no. of e?
? Fe → 3d?4s², Fe? ² → 3d? 24
? Mn → 3d?4s², Mn? ² → 3d? 23
New answer posted
2 months agoContributor-Level 10
R: CH? OH
Certain mild reducing agents like hypophosphorus acid or ethanol reduce diazonium salts to arene and themselves get oxidised to phosphorous acid and ethanal respectively.
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