Chemistry NCERT Exemplar Solutions Class 12th Chapter Fourteen

This is a Multiple Answer Type Questions as classified in NCERT Exemplar

Correct options are a and c.

The cyclic structure of ribose and fructose is five-membered (furanose structures). Like compound furans, they have a five-membered ring.

This is a Multiple Answer Type Questions as classified in NCERT Exemplar

Correct options are a, b and c.

Lysine is an amino acid with the structural formula of (a).

(b) Because the number of groups (two) is more than the number of -COOH groups (one), it is a basic amino acid (one).

Because it is created in human bodies, it is a non-essential amino acid.

This is a Multiple Answer Type Questions as classified in NCERT Exemplar

Correct options are b and d.

Acidic amino acids are divided into two groups, one -COOH group against the other - NH₂ group. As a result, the acidic amino acids (b) and (d) are the only ones among the supplied structures.

This is a Multiple Answer Type Questions as classified in NCERT Exemplar

Correct options are a and c.

Globular protein is a protein structure that forms when a chain of polypeptides coils around to produce a spherical shape. Insulin and albumin are two examples of water-soluble globular proteins. As a result, (a) and (c) are the correct answers.

This is a Multiple Answer Type Questions as classified in NCERT Exemplar

Correct options are b and d.

Sucrose is a common disaccharide that breaks down into an equimolar mixture of D- (+)- glucose and D- (-)- fructose when hydrolyzed. These two monosaccharides are held together by a glycosidic bond between C₁ of α - glucose and C₂ of β fructose. Because the reducing groups of glucose and fructose are involved in the formation of glycosidic linkages, sucrose is a non-reducing sugar.

This is a Multiple Answer Type Questions as classified in NCERT Exemplar

Correct option is C.

The links between C₁ and C₄ of glucose are shown as 'A' and ' C, ' respectively, whilst the linkage between C₁ and C₆ of the glucose units is shown as ' B. ' Furthermore, option (c) is clearly correct based on the structures.

Because ' B ' is the bond or link between the glucose units of C1 and C6 and, option (b) is wrong.

Option (a) is wrong because the relationship between C₁ and C₄ and is represented by 'C.'

Because 'A' is the hyperlink between C₁ and C₄ the glucose units of and, option (d) is wrong.

This is a Multiple Answer Type Questions as classified in NCERT Exemplar

The Correct option is c.

In the cyclic structure of glucose or fructose, anomeric carbon is carbon that is close to an oxygen atom. As shown in the structure above, atoms 'a' and 'b' are close to the oxygen atom, and the hydroxyl groups of both carbon atoms have different orientations.

This is a Multiple Answer Type Questions as classified in NCERT Exemplar

The Correct option is a.

In the same way as (+) glyceraldehyde has a group on the lowest asymmetric carbon on the right side, the I, II, and III structures have a (-OH) group on the lowest asymmetric carbon on the right side giving them a D-configuration.

This is a Multiple Answer Type Questions as classified in NCERT Exemplar

The Correct option is c.

The absence of a free (-CHO) aldehyde group is indicated by the fact that glucose pentaacetate does not react with hydroxylamine. The open structure of glucose cannot account for this, although the open chain structure of glucose can account for all other features.

This is a Multiple Answer Type Questions as classified in NCERT Exemplar

Ans: The Correct option is a.

Anomers are cyclic monosaccharide structures that differ structurally at carbon-1. In this scenario, I and II are anomers since they differ only at carbon -1.