Chemistry

Get insights from 6.9k questions on Chemistry, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry

Follow Ask Question
6.9k

Questions

0

Discussions

22

Active Users

0

Followers

New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

[ F e ( C O ) 4 ( C 2 O 4 ) ] +

x + 4 * 0 – 2 * 1 = +1

x = +3

Fe+3 = 4s0 3d5

In presence of strong ligand, i.e, CO.

Spin only magnetic moment

= n ( n + 2 ) B . M = 1 ( 1 + 2 ) B . M

3 B . M . = 1 . 7 3 B . M

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Electrophilic addition of bromine to an alkene is anti-addition, in which cis-alkene gives two enantiomers and trans – alkene gives meso form

Here; trans-but-2-ene will give meso products

 

New answer posted

a year ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

Electrophilic addition of bromine to an alkene is anti-addition, in which cis-alkene gives two enantiomers and trans – alkene gives meso form

Here; trans-but-2-ene will give meso products

 

New answer posted

a year ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

Structure (I) is anti conformer.

Structure (II) is fully eclipsed conformer.

Structure (III) is skew or gauche conformer.

Structure (IV) is partially eclipsed.

∴ order of stability

(I) > (III) > (IV) > (II)

Order of P.E. is (II) > (IV) > (III) > (I).

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Na/H2 can not reduce a functional group as Na does not behaves as catalyst here.

New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Stability order of oxides (X2O) is,

l2O > Cl2O > Br2O

Bonds of halogen & oxygen are covalent due to less EN difference.

Stability of (I - O) bond is higher due to less polarity and that of (Cl-O) bond is higher due to multiple bonding.

New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

(a) Cell constant = ( l A ) = m / m 2 = m − 1  

(b) molar conductivity ( λ m ) = κ * 1 0 0 0 m o l a r i t y

= Scm2 mol-1

(c) Conductivity ( κ ) = 1 ρ = l R A

= Ω − 1 m − 1                                

(d) degree of dissociation = n u m b e r     o f     m o l e     d i s s o c i a t e d T o t a l     m o l e , it is dimensionless 

New answer posted

a year ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Ethylene glycol (HO – CH2 – CH2 – OH) and terephthalic acid

 

New answer posted

a year ago

0 Follower 31 Views

A
alok kumar singh

Contributor-Level 10

Rate constant depends on temperature as

K = A e − E a / R T              

Here; as T increases rate constant increases exponentially.

New answer posted

a year ago

0 Follower 67 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 67k Colleges
  • 1.2k Exams
  • 716k Reviews
  • 1850k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.