Chemistry

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A
alok kumar singh

Contributor-Level 10

Nucleophilic addition of sodium hydrogen sulphite to aldehyde or ketone is a;

N a H S O 3 ? N a + + H S O 3 ?                

 

So; nucleopilic addition of sodium hydrogen sulphite to an aldehyde or a ketone involves proton transfer to form a stable ion.

Addition of hydrogen cyanide;

Final product is cyanohydrin.

New answer posted

7 months ago

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A
alok kumar singh

Contributor-Level 10

All given oxide have nitrogen – nitrogen bond except N2O5 as ;

 

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A
alok kumar singh

Contributor-Level 10

BOD is biological oxygen demand which represents the amount of oxygen required to degrade organic matter in water.

Higher the BOD more polluted the water is

So; here water sample with BOD = 3 ppm is the cleanest

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7 months ago

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A
alok kumar singh

Contributor-Level 10

Here, C3H6 is propene

   

Second reaction is iodoform reaction.

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V
Vishal Baghel

Contributor-Level 10

Impurities present in electrolytic refining of blister Cu, removed as anode mud

= Sb, Se, Te, Ag, Au, Pt

Ans. = 6

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7 months ago

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V
Vishal Baghel

Contributor-Level 10

N a 2 O + H 2 O 2 N a O H

w = 20 g

V H 2 O = 5 0 0 m L        

Mole of Na2O=   2 0 6 2

? 1 mole of Na2O gives 2 mole of NaOH

( 2 0 6 2 ) mole of Na2O gives ( 2 * 2 0 6 2 ) moles of NaOH

= 2 0 3 1 m o l e    

Molarity of NaOH solution

= 2 0 3 1 * 1 0 0 5 0 0 M = 2 0 3 1 * 2 M = 4 0 3 1 M

= 1.29 M

1 2 . 9 * 1 0 1 M 1 3 * 1 0 1 M

Ans. = 13

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7 months ago

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A
alok kumar singh

Contributor-Level 10

Given are the oxide of alkali and alkaline earth metals which are ionic in nature.

Simple oxide are Li2O, CaO, MgO and K2O.

Peroxide is Na2O2 and superoxide is KO2.

All simple oxides are diamagnetic as it has no unpaired electron.

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7 months ago

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V
Vishal Baghel

Contributor-Level 10

Zn (30) = 1 s 2 2 s 2 2 p 6 3 s 2 3 p 6 4 s 2 3 d 1 0  

Z n + = [ A r ] 4 s 1 3 d 1 0      

Outermost electron is 4s electron,

n = 4 , l = 0 , m = 0 , s = ± 1 / 2         

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7 months ago

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V
Vishal Baghel

Contributor-Level 10

log k = 20.35 - ( 2 . 4 7 * 1 0 3 ) T  

Comparing with,

l o g k = l o g A E a 2 . 3 0 3 R T

E a 2 . 3 0 3 R = 2 . 4 7 * 1 0 3

= 47.29 kJ/mole

Ans. = 47

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