Chemistry

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New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

Calamine is the ore of zinc i.e. ZnCO3.

Malachite is the ore of copper i.e. CuCO3.Cu (OH)2.

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Electronic configuration of Fe is [Ar] 4s23d6 and in +3 oxidation state it has [Ar] 4s03d5 configuration.

New question posted

a year ago

0 Follower 3 Views

New question posted

a year ago

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New answer posted

a year ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

Nucleophilic addition of sodium hydrogen sulphite to aldehyde or ketone is a;

N a H S O 3 ? N a + + H S O 3 ?                

 

So; nucleopilic addition of sodium hydrogen sulphite to an aldehyde or a ketone involves proton transfer to form a stable ion.

Addition of hydrogen cyanide;

Final product is cyanohydrin.

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

All given oxide have nitrogen – nitrogen bond except N2O5 as ;

 

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

BOD is biological oxygen demand which represents the amount of oxygen required to degrade organic matter in water.

Higher the BOD more polluted the water is

So; here water sample with BOD = 3 ppm is the cleanest

New answer posted

a year ago

0 Follower 13 Views

A
alok kumar singh

Contributor-Level 10

Here, C3H6 is propene

   

Second reaction is iodoform reaction.

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Impurities present in electrolytic refining of blister Cu, removed as anode mud

= Sb, Se, Te, Ag, Au, Pt

Ans. = 6

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

N a 2 O + H 2 O → 2 N a O H

w = 20 g

V H 2 O = 5 0 0 m L        

Mole of Na2O=   2 0 6 2

? 1 mole of Na2O gives 2 mole of NaOH

∴ ( 2 0 6 2 ) mole of Na2O gives ( 2 * 2 0 6 2 ) moles of NaOH

= 2 0 3 1 m o l e    

Molarity of NaOH solution

= 2 0 3 1 * 1 0 0 5 0 0 M = 2 0 3 1 * 2 M = 4 0 3 1 M

= 1.29 M

=  1 2 . 9 * 1 0 − 1 M ≈ 1 3 * 1 0 − 1 M

Ans. = 13

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