Chemistry

In reaction ;

  $5F{e}^{2+}+Mn{O}_4^{-}+8H^{+}\to M{n}^{2+}+4H_{2}O+5F{e}^{3+}$              

Colour of Fe²⁺ is green and that of Fe³⁺ is yellow.

$ln{\left[Co{\left(CN\right)}_6\right]}^{4-},$ Co has +2 oxidation state

Hence, electronic configuration of CO2+ is $\left[Ar\right]3d^{7}4s^0$ ${}^{}{}^{}$ . In complex   ${\left[Co{\left(CN\right)}_6\right]}^{4-},$ ${{}_{}}^{}$given ligand CN is strong hence, after pairing in d-subshell, total number of unpaired electron =

$\therefore$ spin magnetic moment =   $\sqrt[]{1\left(1+2\right)}=\sqrt[]{3}=1.73BM$ $\text{exception 25:}\text{exception 25:}$

$=1.73BM\approx 2.0BM$

Kindly conside the following Image

2700 kJ energy released from 180 gm (1 mole) of glucose

$\therefore$ 1 kJ energy released from $\frac{180}{2700}$ gm of glucose

$\therefore$ 10000 kJ energy released from   $\left(\frac{180*10000}{2700}\right)$ gm of glucose

Amount of glucose = $\frac{18000}{27}=666.66\approx 667gm$

$I_3^{-}$ anion has three lone pair

Hydrogen peroxide reduces iodine to iodide ion is basic medium as;

$H_2{O}_2+2O{H}^{-}+l_2\to O_2+2l^{-}+2H_{2}O$

Here A is CH₃ - CH₂ – CH₂ – COO – CH₂ – CH₃

The given sequence of reaction is:

$C{H}_3-C{H}_2-C{H}_2-C{H}_2-OH\underset{}{\overset{Oxidation}{\to }}C{H}_3-C{H}_2-C{H}_2-COOH$

Only 1° aromatic amines give stable diazonium salt on reaction with nitrous acid

Here 1° aromatic amine is  which gives most stable diazonium salt