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New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct option: C

Coordination compounds with the same composition but varying ligand-metal connectivity are known as linkage isomerism.

[Co (NH3)5 (NO2)]2+ , NO2 has two donor sites N and O

[Cr (NH3)5SCN]2+ , S and N are two donor sites.

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct options: A, B and C

Option A, B, and C describe that ethane-1, 2-diamine is a neutral ligand due to its lack of charge, a bidentate ligand due to the presence of two donor sites on one nitrogen atom, and a chelating ligand due to its ability to chelate with metal.

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct option: A and C

Optical compounds are highly imposable compounds that lack symmetry components. As a result, Option A and C are mirror reflections of each other.

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct option: B and D

Heteroleptic is a compound that contains many ligands of various sorts. NH3 and 

Cl as a ligand or also called as donor groups, is a heteroleptic complex.

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct options: A, B and C

A homoleptic complex is one that has only one species or group as a ligand.

Option A, B, and C each have only one ligand, but option D has two.

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a year ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct option: B and C

[Co (H2O)6]2+  is increased when excess of HCl is added. Tetrahedral complexes have smaller crystal field splitting than octahedral complexes because Δt = 4 9 Δ0

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a year ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct option: A and C

For answer at (A) Atomic number of Iron is 26 . In ferricyanide complex, iron is in oxidation state of 3+. The orbitals on the metal atom undergoes d2sp3 hybridizaion and hence the complex has octahedral shape.

Also it can be said that, [Fe (CN)6]3- has one unpaired electron which makes it weakiy paramagnetic. Therefore, option C is also correct.

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct option: A and C

The outer octahedral complexes are weak ligands, number of pairing electrons and high spinning potential.

[MnCl6]3-   - electronic configuration of Mn = 3d5,4s2. Shifting the valence electrons become 

Mn3+ ,3d4 and number of unpaired electrons is 4.

[FeF6]3- - electronic configuration of Fe = 3d6,4s2. Shifting the valence electrons become

Fe3+ ,3d5 and the number of unpaired electrons is 5.

[CoF6]3 - electronic configuration of Co  =  3d7,4s2 shifting the valence electrons become

 Fe3+ ,3d6

...more

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct option: A and C

(i) Orbitals of Co3+ ion d2sp3 hybridised orbitals of Co3+ [Co (NH3)6]3+ (inner orbital or low spin complex)

No. of unpaired electron =0

Magnetic property = diamagnetic, due to absence of unpaired electrons

(ii) Electronic configuration is 3 d6 orbitals of Fe2+ ion:

As CNis a strong field ligand, it causes the pairing of the unpaired 3d electrons. Since there are six ligands around the central metal ion, the most feasible hybridization d2sp3⋅d2sp3 hybridized oribtals of Fe2+ are:

6 electron pairs from CN ions occupy the six hybrid d

...more

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Ans: Correct option: C

[Pt (NH3)2Cl (NO2)] is a neutral molecule. Ligands are arranged alphabetically.

So, NH3 Diammine, chloride and the embedded linkage is nitrogen and last is the metal name.

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