Chemistry

As the difference in $3^{\text{rd}}$ ${}^{}$ and $4^{\text{th}}$ ${}^{}$ ionisation energy is high so atom contains 3 valence electrons. Hence, valency of the atom is 3 and the metal is trivalent. 4 mole of trivalent metal hydroxide will react with 6 mole of ${\mathrm{H}}_2{\mathrm{S}\mathrm{O}}_4$ ${}_{}{}_{}$, $\left(2\mathrm{M}(\mathrm{O}\mathrm{H}{)}_3+3{\mathrm{H}}_2{\mathrm{S}\mathrm{O}}_4?{\mathrm{M}}_2{\left({\mathrm{S}\mathrm{O}}_4\right)}_3+6{\mathrm{H}}_2\mathrm{O}\right)$

The rate of formation of $C$ $$ is three times the rate of decomposition of $$ $A$ .

The reactivity of ${\mathrm{S}}_{\mathrm{N}}1$ ${}_{}$ reaction depends upon stability of carbocation.

Normality $=\frac{\text{Volume strength}}{5.6}=\frac{16.8}{5.6}=3$ $\frac{}{}\frac{}{}$

Molarity $=\frac{\text{Normality}}{n-\text{factor}}=\frac{3}{2}=1.5$

Kindly consider the following Image 

 Photochemical smog has high concentration of oxidising agent like ${\mathrm{N}\mathrm{O}}_2$ ${}_{}$ and ${}_{}$ ${\mathrm{O}}_3$ and is therefore called as oxidising agent.

Chromate ion shape $=$ $$ tetrahedral

But dichromate ion has only one common oxygen bond.

Above a particular concentration called critical micelle concentration at which micelles are formed. for soaps, the $\mathrm{C}\mathrm{M}\mathrm{C}$ $$

 is ${10}^{-4}$ ${}^{}$ to ${10}^{-3}\mathrm{m}\mathrm{o}\mathrm{l}{\mathrm{l}}^{-1}$

Kindly consider the following Image 

$1^{\text{st}}\mathrm{H}$ - atom

$\mathrm{n}=4$

$\mathrm{n}=1$

$4\to \mathrm{3,3}\to \mathrm{2,2}\to 1$

 $4\to 1$ or $4\to \mathrm{3,3}\to 1$

or $4\to \mathrm{2,2}\to 1$

Hence, number of different lines possible $=3+1=4$ $$

Minimally, both can have same transition i.e $4\to 1$ etc.