Chemistry
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3 months agoNew answer posted
3 months agoContributor-Level 10
Key point: Fehling solution do not oxidise aromatic aldehydes, except when EWG present
at O/P position So (I), (III), (IV) not show this test
New question posted
3 months agoNew answer posted
3 months agoContributor-Level 10
According to VSEPR theory:
For the species which contain
Has square pyramidal shape
These are BrF? , ClF? , XeOF?
New answer posted
3 months agoContributor-Level 10
Total number of electron in Ti = 22
Total number of electron in Ti? = 22 – 4 = 18 So EAN value of Ti = 18 + 12 + 4 = 34
New answer posted
3 months agoContributor-Level 10
Factual
⇒ leaching methods is used for those metal in which metal is more soluble than impurities and these are Al, Au, Ag, low grade Cu
New answer posted
3 months agoContributor-Level 10
Initial m equivalent of Cu²? = 200 * 0.5 * 2 = 200 m eq
So electricity passed = (0.965*3600)/96500 = 36 * 10? ³ eq. = 36 m eq
m eq CuBr? remaining = 200 – 36 = 164 ∴ N = meq / V (in ml) = 164/200 = 0.82
New answer posted
3 months agoContributor-Level 10
Mol wt of propane = 44 g and weight of propane = 12.0 g
So, using PV = nRT
V = (nRT)/P = (12/44) * 0.082 * 333) / (740/760) = 7.648 L
New answer posted
3 months agoContributor-Level 10
From ΔT? = K? * m, and ΔT? = 15°C
∴ m = ΔT? / K? = 15 / 1.86 = 8.06
So the amount of propyl alcohol to be added.
= m * molwt = 8.06 * 60 = 483.6 g
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