Chemistry

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3 months ago

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V
Vishal Baghel

Contributor-Level 10

Gutta percha is a synthetic rubber and its monomer is isoprene .
Since isoprene has EDG, so it is prepared by cationic addition polymerization

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3 months ago

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A
alok kumar singh

Contributor-Level 10

Anode      Ag + Br- -> AgBr + e-

Cathode   Ag+ + e- ® Ag

  E o c e l l = ( E o R P ) C ( E o R P ) A        

E c e l l = 0 . 0 6 l o g K s p 0 . 0 6 l o g 1 0 0 0 . 6 4 3 = 0 . 0 6 l o g K s p 0 . 1 2 l o g K s p = 0 . 7 6 3 0 . 0 6 = 1 2 . 7 1            

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New answer posted

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V
Vishal Baghel

Contributor-Level 10

From Reaction

Δn? = 2 – 1 = 1

Kp = Kc (RT)^Δn?

Kp = Kc (RT)¹

Kc = Kp (RT)? ¹

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Vishal Baghel

Contributor-Level 10

Thermal stability of compound is directly proportional to large anion of s-block elements:

T.S ∝ 1/ (PP of cation)

And p.p. ∝ charge ∝ 1/size, So, [T.S. ∝ size ∝ 1/ (charge)]

So, Sr [NO? ]? is highly stable

But Mg (NO? )? ⇒ poor

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Vishal Baghel

Contributor-Level 10

All have same molarity, pH ∝ 1/ (Acidic strength) ∝ Basic strength

H? SO? → Acidic

NH? Cl (Salt of weak base and strong acid)

Acidic but less than H? SO?

NaCl → (Neutral solution)

NaOH → Basic (Strong Base)

So NaOH > NaCl > NH? Cl > H? SO?

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3 months ago

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A
alok kumar singh

Contributor-Level 10

(a)  [1rCl (CO) (PPh3)2] carbonylchloridobis (triphenylphosphine) iridium (I).

(b)  Coordination number of Ir is four. Ir is in (+1) oxidation state with 4d8 configuration. It is trans isomer, so its geometry should be square planar.

(c) All electrons are paired, hence diamagnetic

(d)  Can exhibit GI only.

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New answer posted

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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Vishal Baghel

Contributor-Level 10

and basic strength ∝ 1/pK? ∝ K? ∝ +R ∝ 1/ (-R) ∝ +I ∝ 1/ (-I)

So basic strength order ⇒ IV > III > II > I, so pK? order is IV < III < II < I

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