Chemistry

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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Kindly go through the answers 

(8.00)

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

t = t 1 / 2 l o g 2 . l o g V ∞ V ∞ − V t 2 0 = 1 0 l o g 2 . l o g V ∞ V ∞ − 2 5

∴ V ∞ = 3 3 . 3 3     m l

New answer posted

a year ago

0 Follower 45 Views

V
Vishal Baghel

Contributor-Level 10

Kindly go through the answers

(13.00)

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

q = 0, w = 0, U = 0 = f (V, T)

As volume changes, temperature must change to maintain constant internal energy.

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Ammonical AgNO3   

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V
Vishal Baghel

Contributor-Level 10

Zero acidic hydrogen present in anionic part of (R)

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V
Vishal Baghel

Contributor-Level 10

(Cr, Mn) -> Thermite reduction

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V
Vishal Baghel

Contributor-Level 10

A ( g ) ? 2 B ( g ) .

E m 2 m o l V l 4 m o l V l

N e w       E q m         4 − x V 4 + 2 x V

V * 2 4 − x 2 V   4 − 2 x 2 V

New Eqm 4 − x − y 2 V 4 + 2 x + 2 y 2 V

= 4 − Z 2 V = 4 + 2 Z 2 V ( Z = x + y )

Now, KC =  [ B ] 2 [ A ] = constant

o r , ( 4 V ) 2 ( 2 V ) = ( 4 + 2 Z 2 V ) ( 4 − Z 2 V ) ⇒ Z = 1 . 2 9

 mole of B at new Eqm = 4 + 2Z = 6.58

New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Sucrose D (+) glucose + D (-) Fructose

  [ α ] = + 6 6 . 5 ° [ α ] = + 5 2 . 5 ° [ α ] = − 9 2 . 8 °

Thus rotation changes from positive to negative after hydrolysis. Due to this reason hydrolysis of sucrose is known as inversion and mixture after hydrolysis is known as invert sugar.

Therefore option (B) is correct.

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a year ago

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V
Vishal Baghel

Contributor-Level 10

[ Z n ( g l y ) 2 ] is optically active compound

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