Chemistry

Gutta percha is a synthetic rubber and its monomer is isoprene .
Since isoprene has EDG, so it is prepared by cationic addition polymerization

Anode      Ag + Br^- -> AgBr + e^-

Cathode   Ag⁺ + e^- ® Ag

  ${E^o}_{cell}={\left({E^o}_{RP}\right)}_C-{\left({E^o}_{RP}\right)}_A$        

$\begin{array}{l}{E}_{cell}=-0.06log{K}_{sp}-0.06log100\\ 0.643=-0.06log{K}_{sp}-0.12\\ log{K}_{sp}=-\frac{0.763}{0.06}=-12.71\end{array}$            

From Reaction

Δn? = 2 – 1 = 1

Kp = Kc (RT)^Δn?

Kp = Kc (RT)¹

Kc = Kp (RT)? ¹

Thermal stability of compound is directly proportional to large anion of s-block elements:

T.S ∝ 1/ (PP of cation)

And p.p. ∝ charge ∝ 1/size, So, [T.S. ∝ size ∝ 1/ (charge)]

So, Sr [NO? ]? is highly stable

But Mg (NO? )? ⇒ poor

All have same molarity, pH ∝ 1/ (Acidic strength) ∝ Basic strength

H? SO? → Acidic

NH? Cl (Salt of weak base and strong acid)

Acidic but less than H? SO?

NaCl → (Neutral solution)

NaOH → Basic (Strong Base)

So NaOH > NaCl > NH? Cl > H? SO?

(a)  [1rCl (CO) (PPh₃)₂] carbonylchloridobis (triphenylphosphine) iridium (I).

(b)  Coordination number of Ir is four. Ir is in (+1) oxidation state with 4d⁸ configuration. It is trans isomer, so its geometry should be square planar.

(c) All electrons are paired, hence diamagnetic

(d)  Can exhibit GI only.

and basic strength ∝ 1/pK? ∝ K? ∝ +R ∝ 1/ (-R) ∝ +I ∝ 1/ (-I)

So basic strength order ⇒ IV > III > II > I, so pK? order is IV < III < II < I

Fe acts a catalyst and Mo acts as promoter in Haber's process.

? Solvent is H? O, which is in excess

So using m ( molality ) = (x? *1000)/ (x? * (M? )? )

? x? = 0.74 (Mol? = 18 g)

x? = 1 – 0.74 = 0.26 ∴ m = (0.26 * 1000)/ (0.74 * 18) = 19.5