Class 11th

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New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Number of mol of A reacted = 1*10? = 10?
Number of molecule of A = 10? * 6 *10²³
Quantum efficiency = (6 *10¹? ) / (1.2 *10¹? ) = 0.50

New answer posted

3 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

According to question,

  1 2 ( 1 a + 1 b ) = 1 4         

1 a + 1 b = 1 2 . . . . . . . . ( i )           

Equation of required line is x a + y b = 1  

Obviously B (2, 2) satisfying condition (i)

 

New answer posted

3 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

4x – 3y + k2 = 0

2 r = 4 0 5 = 8 r = 4

( x 1 ) 2 + ( y + 2 ) 2 = 1 6

New answer posted

3 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

ΔG° = – 2.303RT log Kp = – 2.303* 2 * 300log10? ³
= – 2.303* 2 * 300 * (– 3) = 4145.4cal mol? ¹

New answer posted

3 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

P? = 1atm
P? = 1atm * 40/100 = 0.40atm
V? = 100 cm³
V? =?
At constant temperature, P? V? = P? V?
So V? = (P? V? ) / P? = (1atm * 100 cm³) / 0.40 atm = 250cm³
Hence, the volume of bulb B = (250 –100) cm³ = 150 cm³

New answer posted

3 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

As 500g of tooth-paste has = 0.2g of F?
So, 10 g of toothpaste has = (0.2g * 10? g) / 500g F = 400g of F
Hence, concentration in ppm is 400.

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

As 3f-orbital does not exist as value of l cannot be equal to n, hence no electron can be accommodated.

New answer posted

3 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

ΔH_rxn = ΔH_f (N? O, g) + 3ΔH_f (CO? , g) – (2ΔH_f NO? , g) – 3ΔH_f (CO, g)
= 81 + 3* (– 393) – 2 * 34 – 3 (–110)
= 81 – 1179 – 68 + 330 = – 836 kJ

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

ATP has phosphate group, PO? ³?
So x + 4 (– 2) = – 3 or x = + 5

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

One mole of water is converted to vapour at its boiling point which is 100°C and at 1 atm. For this process ΔG = 0. As phase transformation of water is an equilibrium process and at equilibrium, free energy change is always zero.

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