Class 11th

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New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

(Q? - Q? )/Q? = (T? - T? )/T? ; Q = (300/600) * 1600 = 800 J
work done = Q? - Q? = 1600 – 800 = 800J

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

f? = 300 Hz
3rd overtone = 7f? = 2100 Hz

New answer posted

3 months ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

x = 8R/2 ; y = 5R/2 ; x/y = 8/5 = 1.6

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

Molybdenum oxide is used to convert alkane to aldehyde i.e. propane to propanal

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3 months ago

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V
Vishal Baghel

Contributor-Level 10

When relative sliding stops, both move with same velocity.
Only friction acts in horizontal direction.
∴ for system no external force, we can apply conservation of momentum.
1 * 12 + 5 * 0 = 6 * v
v = 2 m/s
Now work done by friction on block = change in kinetic energy of block
w = (1/2)m (2² - 12²) = (1/2) (1) (4 - 144) = (1/2) (-140) = -70 J

New answer posted

3 months ago

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R
Raj Pandey

Contributor-Level 9

(A) and (C) are staggered conformation. In (A) dihedral angle is 60° and in (C) dihedral angle is 180°.

Dihedral angle is angle between two specified groups.

In (C) it has maximum angle.

New answer posted

3 months ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

Using parallel axis theorem for the side BC, the moment of inertia of the triangle about an axis passing through A and perpendicular to the plane of the triangle,
I? = 2 [ (1/3)ma²] + [ (1/12)ma² + m (√3a/2)²] = (3/2)ma²
If the angular velocity of the triangle at any instant is ω, the velocity of the vertex B at that instant is aω
Therefore, the velocity of B is maximum at the instant the angular velocity is maximum, i.e. when the side BC becomes horizontal
Let the angular velocity at this instant be ω?
Then, by conservation of energy
Gain in kinetic energy = Loss in potential energy
(1/2)I? ω²? = 3mg (Loss in height of CM of tr

...more

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Centripetal acceleration is provided by friction force. Maximum friction force should be equal to or greater that mv² / R.
µmg = mv²/R ; µ = 100/ (100*10) ; µ = 1/10 ; µ = 0.1

New answer posted

3 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Pitch p = 0.5 mm
Device has +ve zero error
R = 6p + 28p/50 - 4p/50 = 6p + 24p/50; 3mm + (24/50) * 0.5 = 3.24 mm

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