Class 11th

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New answer posted

4 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

4t = 100 * (4/3)π * (40π * 10? * 0.01)³
t = 2.5 * 10? ¹¹ cm = 2.5 * 10? ¹³ m

New answer posted

4 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

P, Q, R represents some students which play all three games. Hence no any option is correct.

New question posted

4 months ago

0 Follower 4 Views

New answer posted

4 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Assuming the rope in the boy's hand is vertical and using a Free Body Diagram (FBD):
f? = T
R + T = 90 ⇒ R = 90 - T
For the piece of wood not to move, f? ≤ µR:
T ≤ 0.5 (90 - T) ⇒ T ≤ 30N

New answer posted

4 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

l = 10.0 ± 0.1cm.
T = (100 ± 1) / 200 = 0.5 ± 0.005

New answer posted

4 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

4 months ago

0 Follower 45 Views

A
alok kumar singh

Contributor-Level 10

The x and y coordinates of the center of mass are given by:
x? = y? = 4a / 3π

New answer posted

4 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

The minimum force F? is calculated as:
F? = (μmg) / √* (1 + μ²)* = ( (1/√3) * 1 * 10 ) / √* (1 + (1/√3)²) = 5N

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider then following figure

New answer posted

4 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

A? √* (K? /m)* = A? √* (K? /m)* ⇒ A? √K? = A? √K?

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