Class 11th

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New answer posted

7 months ago

0 Follower 17 Views

R
Raj Pandey

Contributor-Level 9

Apply conservation of momentum along y-axis, we can write
10v? - 10v? sin 30° = 0
⇒ v? = 20m/s

New answer posted

7 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

Deceleration, a = u² / 2S = 10² / (2 * 0.5) = 100 m/s².
Retarding force, F = MA = 0.1 * 100 = 10N

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

7 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

-SO? H acts as a cation exchanger.

-NH? acts as an anion exchanger.

New answer posted

7 months ago

0 Follower 21 Views

V
Vishal Baghel

Contributor-Level 10

We need to find the remainder of (2021)³? ² when divided by 17.
First, find the remainder of 2021 divided by 17.
2021 = 17 * 118 + 15.
So, 2021 ≡ 15 (mod 17).
Also, 15 ≡ -2 (mod 17).
So, (2021)³? ² ≡ (-2)³? ² (mod 17).
(-2)³? ² = 2³? ² = (2? )? ⋅ 2² = 16? ⋅ 4.
Since 16 ≡ -1 (mod 17),
16? ⋅ 4 ≡ (-1)? ⋅ 4 (mod 17).
≡ 1 ⋅ 4 (mod 17)
≡ 4 (mod 17).
The remainder is 4.

New answer posted

7 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

7 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

Given equation of tangent is 2x - y + 1 = 0
equation of normal is x + 2y = 12
Solving with x - 2y = 4 we get centre at (6,2) radius = √ (36 + 9) = √45 = 3√5.

New answer posted

7 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

7 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

The expansion is (x + x^ (log? x)?
The (r+1)-th term is T? =? C? * x? * (x^ (log? x)?
The 4th term means r=3.
T? =? C? * x? * (x^ (log? x)³ = 35 * x? * x^ (3 log? x) = 35 * x^ (4 + 3 log? x).
Given T? = 4480.
35 * x^ (4 + 3 log? x) = 4480
x^ (4 + 3 log? x) = 4480 / 35 = 128.
x^ (4 + 3 log? x) = 128.
Take log? on both sides:
log? (x^ (4 + 3 log? x) = log? (128)
(4 + 3 log? x) * (log? x) = 7
Let t = log? x.
(4 + 3t)t = 7
3t² + 4t - 7 = 0
3t² - 3t + 7t - 7 = 0
3t (t-1) + 7 (t-1) = 0
(3t+7) (t-1) = 0
t = 1 or t = -7/3.
log? x = 1 ⇒ x = 2¹ = 2.
log? x = -7/3 ⇒ x = 2^ (-7/3).
Since x ∈ N, x = 2.

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