Class 11th
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New answer posted
10 months agoNew answer posted
10 months agoContributor-Level 10
Given the decay equation A = A? e^ (-bt/m):
-bt/m = ln (A/A? )
Solving for b:
b = (-m/t? ) * ln (A/A? ) = (-1 / (2 * 60) * ln (6/12) = 5.775 * 10? ³ kg/s
New answer posted
10 months agoContributor-Level 10
n (s) = 6² = 36
E = { (1, 1), (1, 2), (1, 3), (1, 5), (1, 7), (2, 1), (2, 2), (2, 3), (2, 5), (3, 1), (3, 2), (3, 3), (3, 5), (5, 1), (5, 2), (5, 3), (7, 1)}
∴ n (E) = 17
Required prob. = n (E) / n (S) = 17 / 36
New answer posted
10 months agoContributor-Level 10
The bulk modulus B is calculated as:
B = -ΔP / (ΔV/V) = (ρgh) / (ΔV/V) = (10³ * 9.8 * 2 * 10³) / (1.36 * 10? ²) = 1.44 * 10? N/m²
New answer posted
10 months agoContributor-Level 10
The angular frequency ω is calculated as:
ω = 2πf = 2 * 3.14 * 245 = 1.5386 * 10³ rad/s ≈ 1.5 * 10³ rad/s
This continues the solution from number 15 on the previous page.
k = ω / v = (1.53 * 10³) / 300 = 5.1 m? ¹
A = 0.06 / 2 = 0.03m
New answer posted
10 months ago
Contributor-Level 10
Pressure decreases with an increase in volume in both isothermal and adiabatic processes. In an adiabatic process, as volume decreases, pressure increases with the increase in temperature.
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