Class 11th
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New question posted
2 months agoNew answer posted
2 months agoContributor-Level 10
We need to find the remainder of (2021)³? ² when divided by 17.
First, find the remainder of 2021 divided by 17.
2021 = 17 * 118 + 15.
So, 2021 ≡ 15 (mod 17).
Also, 15 ≡ -2 (mod 17).
So, (2021)³? ² ≡ (-2)³? ² (mod 17).
(-2)³? ² = 2³? ² = (2? )? ⋅ 2² = 16? ⋅ 4.
Since 16 ≡ -1 (mod 17),
16? ⋅ 4 ≡ (-1)? ⋅ 4 (mod 17).
≡ 1 ⋅ 4 (mod 17)
≡ 4 (mod 17).
The remainder is 4.
New answer posted
2 months agoContributor-Level 10
Given equation of tangent is 2x - y + 1 = 0
equation of normal is x + 2y = 12
Solving with x - 2y = 4 we get centre at (6,2) radius = √ (36 + 9) = √45 = 3√5.
New answer posted
2 months agoContributor-Level 10
The expansion is (x + x^ (log? x)?
The (r+1)-th term is T? =? C? * x? * (x^ (log? x)?
The 4th term means r=3.
T? =? C? * x? * (x^ (log? x)³ = 35 * x? * x^ (3 log? x) = 35 * x^ (4 + 3 log? x).
Given T? = 4480.
35 * x^ (4 + 3 log? x) = 4480
x^ (4 + 3 log? x) = 4480 / 35 = 128.
x^ (4 + 3 log? x) = 128.
Take log? on both sides:
log? (x^ (4 + 3 log? x) = log? (128)
(4 + 3 log? x) * (log? x) = 7
Let t = log? x.
(4 + 3t)t = 7
3t² + 4t - 7 = 0
3t² - 3t + 7t - 7 = 0
3t (t-1) + 7 (t-1) = 0
(3t+7) (t-1) = 0
t = 1 or t = -7/3.
log? x = 1 ⇒ x = 2¹ = 2.
log? x = -7/3 ⇒ x = 2^ (-7/3).
Since x ∈ N, x = 2.
New answer posted
2 months agoContributor-Level 10
Circle S? : x² + y² - 10x - 10y + 41 = 0.
Center C? = (5, 5). Radius r? = √ (5² + 5² - 41) = √ (25 + 25 - 41) = √9 = 3.
Circle S? : x² + y² - 16x - 10y + 80 = 0.
Center C? = (8, 5). Radius r? = √ (8² + 5² - 80) = √ (64 + 25 - 80) = √9 = 3.
The solution checks if the center of one circle lies on the other.
Put C? (8, 5) into S? : 8² + 5² - 10 (8) - 10 (5) + 41 = 64 + 25 - 80 - 50 + 41 = 130 - 130 = 0. So C? lies on S?
Put C? (5, 5) into S? : 5² + 5² - 16 (5) - 10 (5) + 80 = 25 + 25 - 80 - 50 + 80 = 130 - 130 = 0. So C? lies on S?
This means both circles pass through the center of each other. So statement (D) is co
New answer posted
2 months agoContributor-Level 10
By property of triangle image of vertex of P is Q about the perpendicular side bisector of triangle Hence according to question X - Y = 0 is a perpendicular side bisector of PQ
Hence solving X - Y = 0 and 2X - y + 2= 0
o (-2, -2)
New answer posted
2 months agoContributor-Level 10
4t = 100 * (4/3)π * (40π * 10? * 0.01)³
t = 2.5 * 10? ¹¹ cm = 2.5 * 10? ¹³ m
New answer posted
2 months agoContributor-Level 10
P, Q, R represents some students which play all three games. Hence no any option is correct.
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