Class 11th

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New answer posted

11 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

x = A s i n ω t

Angle travelled by while moving from A to B

θ = 3 0 ° = π ° 6

θ = ω t

π 6 = ω * 3 [ t = 3 s e c ]

ω = π 1 8

T = 2 π ω = 2 π * 1 8 π = 3 6 s e c

T = 36 sec

 

New answer posted

11 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

mg = pvg

mg = d1vg           ……. (i)

Fb = weight of fluid displaced = d2vg         …… (ii)

by NLM 1            Fb + Fv = mg

FV = mg - Fb

F v = m g ( 1 d 2 d 1 )

New answer posted

11 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Com (Conservation of Momentum)

Pi = Pf

m u 1 + 5 m u 2 = m v 1 + 5 m v 2

m u 1 = m v 1 + 5 m v 2

u 1 + v 1 + 5 v 2  …….(i)

& e = 1 = v 2 v 1 U 1 U 2 = v 2 v 1 u 1

  u 1 = v 2 v 1 …….(ii)

Equation (i) + (ii)

k . E T = 5 9 ( K . E ) i = 5 5 . 6 %

 

New answer posted

11 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

The law of gravitation holds good for any pair of bodies in the universe.

This is correct statement.

The weight of any person becomes zero when the person is at the centre of the Earth.

Weight = mg

= m * 0 [g = 0 at the centre of the Earth]

= 0

New answer posted

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

V r m s > V a v > V m p

New answer posted

11 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

To keep,   Δ α c m = 0

     

      M 1 Δ x 1 + M 2 Δ X 2 = 0          

1 0 * 6 + 3 0 Δ X 2 = 0      

Δ X 2 = 1 0 * 6 3 0

Δ X 2 = 2 c m        

i.e. 2 cm towards the 10 kg block.

New answer posted

11 months ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

Assume both the block is moving with common acceleration 'a' then

a = F m + M . . . . . . . ( i )

N = mg

N = 2g

f = m a = m F m + M

For no slipping

2 F 1 0 g

F 5 g

F 5 * 9 . 8 F 4 9 . 0 N

New answer posted

11 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

C l > F   (exception)

S > Se (size effect)

L i > N a   (size effect)

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Given, m = 0.6 ±  0.006

p = m v = m π r 2 l

Δ ρ ρ * 1 0 0 = Δ m m * 1 0 0 + 2 Δ r r * 1 0 0 + Δ l l * 1 0 0

= 1 + 2 * 1 + 1

New answer posted

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

N 2 + O 2 ? 2 N O

Oxidation state changes

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