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Vishal Baghel

Contributor-Level 10

Environmental chemistry is a branch of environmental studies. Environmental studies deal with the sum of all social, economical, biological, physical and chemical interrelations with our surroundings. Environmental chemistry deals with the study of the origin, transport, reactions, effects and fates of chemical species in the environment

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Payal Gupta

Contributor-Level 10

3.24.  (a) Gain of an electron leads to the formation of an anion. The size of an anion will be larger than that of the parent atom because the addition of one or more electrons would result in increased repulsion among electrons and decrease in effective nuclear charge.

(b) Loss of an electron from an atom results in the formation of a cation. A cation is smaller than its parent atom because it has former electrons while its nuclear charge remains the same.

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Payal Gupta

Contributor-Level 10

3.23. On Pauling scale, the electronegativity of nitrogen is 3.0 which indicates that it is quite electronegative. But it is not correct to say that the electronegativity of nitrogen in all the compounds is 3. It varies with the atoms that N is bonded with. For example, in NH3, N has a different electronegativity than N in NO2

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Payal Gupta

Contributor-Level 10

3.22. Electron gain enthalpy refers to tendency of an isolated gaseous atom to accept an additional electron to form a negative ion. Whereas electronegativity refers to tendency of the atom of an element to attract shared pair of electrons towards it in a covalent bond.

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Payal Gupta

Contributor-Level 10

3.21. When an electron is added to oxygen atom, energy is released to form a negative ion. This enthalpy change called the first electron gain enthalpy is thus negative. On adding another electron to the O? ion, it experiences repulsion from the anion due to which the instability of the ion increases. Thus, the addition of the second electron requires energy due to which the second electron gain enthalpy is positive.

O + e? ? O?     ? H1 = -141KJ

O? + e? ? O2?   ? H2 = 780 KJ

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Payal Gupta

Contributor-Level 10

Solution:

Enthalpy in simple terms means chemical energy, the Electron Gain Enthalpy is equal to the energy released or absorbed when an atom gains an electron to form a anion (in gaseous state).

The Negative ion enthalpy is measured when net amount of energy decreases. This happens when atom releases some amount of energy in an Exothermic process.

(i) O or F:

The electronic configuration of O and F are:

O: 1s2 2s2 2p4

F: 1s2 2s2 2p5

Fluorine (F) has a more negative electron gain enthalpy than oxygen (O) because of its smaller size and its valency.

Due to smaller size, all electrons feels stronger electrostatic attraction f

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Payal Gupta

Contributor-Level 10

3.19. On moving down the group, the ionization enthalpy decreases. This is true for B and Al due to the bigger size of Al.

The ionization enthalpy of Ga is unexpectedly higher than Al because Ga contains 10d electrons in inner shell whose shielding is less effective than that of s and p electrons.

The outer electron is held fairly strongly by the nucleus. The ionization enthalpy increases slightly. A similar increase is observed from In to Tl due to presence of 14f electrons in the inner shell of Tl which have poor screening effect.

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Payal Gupta

Contributor-Level 10

Atomic size: With the increase in atomic size, the number of electron shells increase. Therefore, the force that binds the electrons with the nucleus decreases. The ionization enthalpy thus decreases with the increase in atomic size.

Screening or shielding effect of inner shell electron: With the addition of new shells, the number of inner electron shells which shield the valence electrons increases. As a result, the force of attraction of the nucleus for the valence electrons further decreases and hence the ionization enthalpy decreases.

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Payal Gupta

Contributor-Level 10

3.17. Electronic configuration of Na and Mg are

Na = 1s2 2s2 2p6 3s1
Mg = 1s2 2s2 2p6 3s2

First electron in both cases has to be removed from 3s-orbital but the nuclear charge of Na (+ 11) is lower than that of Mg (+ 12) therefore first ionization energy of sodium is lower than that of magnesium.
After the loss of first electron, the electronic configuration of

Na+ = 1s2 2s2 2p6
Mg+ = 1s2 2s2 2p6 3s1

Here electron is to be removed from inert (neon) gas configuration which is very stable and hence removal of second electron from Na+ requires more energy in comparison to Mg.
T

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6 months ago

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Payal Gupta

Contributor-Level 10

3.16.  (i) In the electronic configuration of Be (1s2 2s2) the outermost electron is present in 2s-orbital while in B (1s2 2s2 2p1) it is present in 2p-orbital. Since 2s – electrons are more strongly attracted by the nucleus than 2p-electrons, therefore, lesser amount of energy is required to knock out a 2p-electron than a 2s – electron.

Therefore, Be has higher? I H than that of B.

(ii) The electronic configuration of oxygen is 1s2 2s2 2p4. The 2p orbital contains 4 electrons out of which 2 are present in the same 2p-orbital. Due to this, the electron repulsion increases. N has stable half-filled configuration.

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