Class 12th

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New answer posted

8 months ago

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A
alok kumar singh

Contributor-Level 10

E c e l l = ( E R H S o E L H S o ) R P 0 . 0 5 9 1 n l o g 1 0 Q

Q = [ Z n + + ] [ C u + + ] = 0 . 0 4 0 . 0 2 a n d n = 2

E c e l l = ( 0 . 3 4 + 0 . 7 6 ) 0 . 0 5 9 1 2 l o g 1 0 0 . 0 4 0 . 0 2

= 1 . 1 0 . 0 5 9 1 2 * 0 . 3 0 1 0 = 1 . 0 9 1 V = 1 0 9 * 1 0 2 V

 

New answer posted

8 months ago

0 Follower 16 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

8 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

[ F e ( C N ) 5 N O S ] 4   Violet colour

  [ F e ( S C N ) 6 ] 4 Blood red colour

F e 4 [ F e ( C N ) 6 ] 3 H 2 O  Prussian blue colour

[ F e ( C N ) 6 ] 4  Yellow colour

New answer posted

8 months ago

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A
alok kumar singh

Contributor-Level 10

[ P t C l 4 ] 2 + H 2 O ? [ P t ( H 2 O ) C l 3 ] + C l  

At equilibrium  d x d t = 0 , hence

0 = d [ [ P t C l 4 ] 2 ] d t = 4 . 8 * 1 0 5 [ [ P t C l 4 ] 2 ] 2 . 4 * 1 0 3 [ [ P t ( H 2 O ) C l 3 ] ] [ C l ]           

K c = K f K b = 4 . 8 * 1 0 5 2 . 4 * 1 0 3              

= 2 * 10-2

= 0.02

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Cu2Cl2 + Water -> Insoluble

AgCl + Water -> Insoluble

ZnCl2 + Water -> Colouless solution

CuCl2 + Water -> Coloured solution due to 3d9 electronic configuration.

New answer posted

8 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Molar conductivity measured at infinite dilution is called limiting molar conductivity. Hence at infinite dilution stage, both strong electrolyte (KCl) and weak electrolyte (CH3COOH) have identical value of conductivity. Therefore statement – I is false.

Statement – II is also false because molar conductivity increases by the decreasing the concentration of electrolyte.

New answer posted

8 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Molar weight of BaSO4 = 233 gram

233 gm of BaSO4 has 32 gm of S content

Hence 1.44 gm of BaSO4 has ( 3 2 * 1 . 4 4 2 3 3 ) g of S content = 0.1977 gm of 'S'

Weight of sulphur = 0.2 gram (the nearest)

Weight of organic sample = 0.471 gram

% of Sulphur = 0 . 2 * 1 0 0 0 . 4 7 1 = 4 2 . 4 6 %  

the nearest = 42%

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

8 months ago

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P
Payal Gupta

Contributor-Level 10

R4 → D5 → DR2

The least cost to reach to AAB is for AE. And that is BD to AE is zero.

New answer posted

8 months ago

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P
Payal Gupta

Contributor-Level 10

If you look for large figures you would find them in both tables in D5.

 the largest cost = 1157.7 + 1035.3

= 2193.00

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