Class 12th

Clearly, from the graph it could be either Dr. Sharma or Dr. Goyal.

For Dr. Sharma

$=\frac{913.63-750.3}{913.63}*100=24.48$

For Dr. Goyal $=\frac{962.58}{720.93}*100=25.16$

Hence, Dr. Goyal's turnover is maximum.

Electronic configuration of

Gd is ; Gd₆₄ = [Xe]4f⁷ 5d¹ 6s²

Hence $G{d}_{64}^{++}=\left[Xe\right]4f^{7}5d^{1}6s^0$

Total number of electrons in 4f sub-shell = 7

Ans. = 7

Molecular structure of tetrapeptide Gly-Glu-Asp-Tyr is;

Total negative charge developed at pH 12.5 = 4

Ans. = 4

Average income for 2019-20

$=\frac{962.58+1171.01+681.98+913.63+1122.66}{5}$

= 970.372

Average income for 2018-19

$=\frac{720.93+1089.3+731.11+750.31+847.78}{5}$

= 827.886

Thus, difference = 970.372 – 827.886 = 142.48

KCl solution has molality (m) = 3.3, [Means 3.3 mol of KCl dissolved in 1 kg of solved]

Total mass of solution = mass of solute + mass of solvent

= 3.3 * 74.5 + 1000 gm

= 1245.85 gm

Volume of solution = $\frac{Mass}{density}=\frac{1245.85}{1.2}=1038.20ml$

$M=\frac{moles*1000}{V\left(ml\right)}=\frac{3.3*1000}{1038.2}=3.17M$          

Ans. = 3 (the nearest integer)

If Rate = $K{\left[NO\right]}^a{\left[H_2\right]}^b$  

Case I => $7*10^{-9}=K{\left(8*10^{-5}\right)}^a{\left(8*10^{-5}\right)}^b$

Case II =>   $2.1*10^{-8}=k{\left(24*10^{-5}\right)}^a{\left(8*10^{-5}\right)}^b$

Therefore, $\frac{7\text{?}*10^{-1}}{2.1}={\left(\frac{1}{3}\right)}^a$

or ${\left(\frac{1}{3}\right)}^1={\left(\frac{1}{3}\right)}^a\therefore a=1$           

Ans. = 1

New expenditure of C7

= 1.4*365253

= 511354.2

Expenditure of Nigeria = 798294

Nigeria > C7

Expenditure of France= 1210988

France > Austria,

Molecular formula of Mohr' salt, FeSO₄. (NH₄)₂SO₄.6H₂O.

Molecular formula of potash alum = K₂SO₄.Al₂ (SO₄)₃.24H₂O. Overall molecular formula of potash alum = KAl (SO₄)₂. 12H₂O. Ratio of water molecules in Mohr' salt and Potash alum

$=\frac{6}{12}=\frac{1}{2}=0.5=5*10^{-1}$       

Ans. = 5

The difference between the growth rate of UK & France during 2020 – 21 was (28.4 – 5.1) = 23.3% while Vietnam's exports growth rate is 23.4%.

All the solution have higher ion production with respect to 0.1 M C₂H₅OH i.e. 0.1 M Ba₃ (PO₄)₂, 0.1 M Na₂SO₄, 0.1 M KCl and 0.1 M Li₃PO₄. Hence all have lowered freezing point than 0.1 M C₂H₅OH (which is non-ionisable in aqueous medium).

Ans. = 4