Class 12th

$\mathrm{}{\mathrm{M}\mathrm{A}}_2{\mathrm{B}}_2$ shows geometrical and not optical isomerism.

$F=qE\left[E=\frac{\sigma }{{\epsilon }_0}\right]$

$F=\frac{q\sigma }{{\in }_0}=10N$

Final case – Now one plate is removed, Electric field will becomes half; So, force will become half.

$F\text{'}=\frac{10}{2}=5N$

$\lambda =\frac{h}{mv}=\frac{h}{\sqrt[]{2MK.E}}$

$\lambda \alpha \frac{1}{\sqrt[]{m}}$

$\Rightarrow {\lambda }_{\alpha }\sqrt[]{m_{\alpha }}={\lambda }_{C_{12}}\sqrt[]{m_{C_{12}}}$

$\Rightarrow \frac{{\lambda }_{\alpha }}{{\lambda }_{C_{12}}}=\sqrt[]{\frac{m_{C_{12}}}{m_{\alpha }}}=\sqrt[]{\frac{12}{4}}=\sqrt[]{3}:1$

Carbon-chlorine bond cleavage is not possible in ${\mathrm{C}\mathrm{H}}_3=\mathrm{C}\mathrm{H}-\mathrm{C}\mathrm{l}$

Ultraviolet rays – sterilizing surgical instrument

Microwaves – Radar system

Infrared waves – Greenhouse effect

X-rays – Study crystal structure

Given, I = 5 sin (120πt), $\omega$ $$ = 120

$T=\frac{2\pi }{\omega }$

$T=\frac{2\pi }{120\pi }=\frac{1}{60}sec,\frac{T}{4}=\frac{1}{60*4}=\frac{1}{240}sec$

Each ion makes a definite contribution irrespective of the other ion

$\begin{array}{rr}& {\left({\mathrm{\Lambda }}_{\mathrm{m}}^0\right)}_{\mathrm{N}\mathrm{a}\mathrm{B}\mathrm{r}}-{\left({\mathrm{\Lambda }}_{\mathrm{m}}^0\right)}_{\mathrm{N}\mathrm{a}\mathrm{l}}={\mathrm{\Lambda }}_{{\mathrm{m}\mathrm{B}\mathrm{r}}^{-}}^0-{\mathrm{\Lambda }}_{{\mathrm{m}}_{{\mathrm{r}}^{-}}}^0\\ & {\left({\mathrm{\Lambda }}_{\mathrm{m}}^0\right)}_{\mathrm{K}\mathrm{B}\mathrm{r}}-{\left({\mathrm{\Lambda }}_{\mathrm{m}}^0\right)}_{\mathrm{N}\mathrm{a}\mathrm{B}\mathrm{r}}={\mathrm{\Lambda }}_{{\mathrm{m}\mathrm{K}}^{+}}^0-{\mathrm{\Lambda }}_{{\mathrm{m}\mathrm{N}\mathrm{a}}^{+}}^0\end{array}$

Given, x = 99

${\mu }_0=4\pi *10^{-7}Wb/A-m$

${}_{}$ ${\mu }_m=?$   (Permeability of the material)

${\mu }_m=4\pi *10^{-5}$

 Al equilibrium

${\mathrm{K}}_{\mathrm{f}}\left. [{\mathrm{H}}_2\right][\mathrm{N}\mathrm{O}{]}^2=\frac{{\mathrm{K}}_{\mathrm{b}}\left. [{\mathrm{N}}_2\right]{\left. [{\mathrm{H}}_2\mathrm{O}\right]}^{+}}{\left. [{\mathrm{H}}_2\right]}$