Class 12th

Ultraviolet rays – sterilizing surgical instrument

Microwaves – Radar system

Infrared waves – Greenhouse effect

X-rays – Study crystal structure

Given, I = 5 sin (120πt), $\omega$ $$ = 120

$T=\frac{2\pi }{\omega }$

$T=\frac{2\pi }{120\pi }=\frac{1}{60}sec,\frac{T}{4}=\frac{1}{60*4}=\frac{1}{240}sec$

Each ion makes a definite contribution irrespective of the other ion

$\begin{array}{rr}& {\left({\mathrm{\Lambda }}_{\mathrm{m}}^0\right)}_{\mathrm{N}\mathrm{a}\mathrm{B}\mathrm{r}}-{\left({\mathrm{\Lambda }}_{\mathrm{m}}^0\right)}_{\mathrm{N}\mathrm{a}\mathrm{l}}={\mathrm{\Lambda }}_{{\mathrm{m}\mathrm{B}\mathrm{r}}^{-}}^0-{\mathrm{\Lambda }}_{{\mathrm{m}}_{{\mathrm{r}}^{-}}}^0\\ & {\left({\mathrm{\Lambda }}_{\mathrm{m}}^0\right)}_{\mathrm{K}\mathrm{B}\mathrm{r}}-{\left({\mathrm{\Lambda }}_{\mathrm{m}}^0\right)}_{\mathrm{N}\mathrm{a}\mathrm{B}\mathrm{r}}={\mathrm{\Lambda }}_{{\mathrm{m}\mathrm{K}}^{+}}^0-{\mathrm{\Lambda }}_{{\mathrm{m}\mathrm{N}\mathrm{a}}^{+}}^0\end{array}$

Given, x = 99

${\mu }_0=4\pi *10^{-7}Wb/A-m$

${}_{}$ ${\mu }_m=?$   (Permeability of the material)

${\mu }_m=4\pi *10^{-5}$

 Al equilibrium

${\mathrm{K}}_{\mathrm{f}}\left. [{\mathrm{H}}_2\right][\mathrm{N}\mathrm{O}{]}^2=\frac{{\mathrm{K}}_{\mathrm{b}}\left. [{\mathrm{N}}_2\right]{\left. [{\mathrm{H}}_2\mathrm{O}\right]}^{+}}{\left. [{\mathrm{H}}_2\right]}$

$\Rightarrow I_{g}G=\left(l-l_g\right)8\Rightarrow l_g*72=\left(l-l_g\right)8\Rightarrow 9l_g=l-l_g$

$10l_g=l{l}_g=\frac{1}{10}l$

% of I which passes through galvanometer

$$ $l_g=10\mathrm{\%}$  of I

$6\mathrm{N}\mathrm{a}\mathrm{O}\mathrm{H}+3{\mathrm{C}\mathrm{l}}_2?5\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}+{\mathrm{N}\mathrm{a}\mathrm{C}\mathrm{l}\mathrm{O}}_3+3{\mathrm{H}}_2\mathrm{O}$

$2\mathrm{C}\mathrm{a}(\mathrm{O}\mathrm{H}{)}_2+{\mathrm{C}\mathrm{l}}_2?\mathrm{C}\mathrm{a}(\mathrm{O}\mathrm{C}\mathrm{l}{)}_2+{\mathrm{C}\mathrm{a}\mathrm{C}\mathrm{l}}_2+{\mathrm{H}}_2\mathrm{O}$