Class 12th

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New answer posted

11 months ago

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V
Vishal Baghel

Contributor-Level 10

In primary rainbow, red colour is at top and violet is at bottom.

Intensity of secondary rainbow is less in comparison to primary rainbow.

New answer posted

11 months ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

λ electron   = h 2 m E λ electron   λ photon   = 1 c E 2 m

λ photon   = h c E

New answer posted

11 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

Current in capacitor l = V X C

I = v * ( ω c )

C = 1 v ω = 6 . 9 * 1 0 6 2 3 0 * 6 0 0 = 5 0 p F

New answer posted

11 months ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

Assuming current 'i' In outer loop magnetic field at centre

= 4 * μ 0 4 π i L / 2 * [ 2 s i n 4 5 ° )

= 2 2 μ 0 i π L

M = F m α t h r o u g h i n n e r l o o p i

= 2 2 μ 0 i l 2 π L = 2 2 μ 0 l 2 π L

New answer posted

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Total power is  ( 15 * 45 ) + ( 15 * 100 ) + ( 15 * 10 ) + ( 2 * 1000 ) = 4325 W

So, current is 4325 220 = 19.66 A

Answer is 20 A m p .

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

f = 1 2 π L C

f α 1 C

Another capacitor should be added in series with the first capacitor.

New answer posted

11 months ago

0 Follower 16 Views

A
alok kumar singh

Contributor-Level 10

Since magnetic force cannot change the speed. So only electric field which is along -direction will change the speed along -direction only.

v x = E 0 q m t but v y = v 0  

2 v 0 = v x 2 + v y 2

4 v 0 2 = E o 2 q 2 t 2 m 2 + v 0 2
t = 3 m v o q E o

 

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Radius of circular path R = 2 m k q B

q = 2 m k R B

q 1 q 2 = m 1 m 2 * R 2 R 1 = 9 4 * 5 6 = 5 4

New answer posted

11 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

Q = CV

V = Q C

Straight line with slope = 1 C ?

S l o p e = 1 C = 1 2 * 1 0 6 = 5 * 1 0 5

New answer posted

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

i = V r 1 - e - R t / L = 4 1 - e - 500 t

At  t =

i 1 = 4 A

at  t = 40 s

i 2 = 4 1 - e - 20000

= 4 1 - 1 e 2 10000
= 4 1 - 1 ( 7.389 ) 10000
i 1 i 2  is slightly greater than 1 .

 

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