Class 12th

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New answer posted

11 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

 Leq=L1+L22M

New answer posted

11 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

If size of object is very small as compare to wave length of EM wave in free space then, scattering will happen.

New answer posted

11 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Metals                Li Na K Rb                        Cs

Colour               Crimson red Yellow                 Violet                  Red violet  Blue

Wavelength       670.8  589.2  766.5    &nbs

...more

New answer posted

11 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 u=MBcosθ2 (MBcosθ1)

=MB (cosθ2cosθ1)=2*105*14*105 (cos60°cos0°)

=28 (121)

=282=14J

New answer posted

11 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

Since

E.B=0 (EB)

&E0B0=C=3*108m/sec

for option D

E0B0=301.62+452.421061.52+12=301.6*106=3.01*108m/sec

New answer posted

11 months ago

0 Follower 35 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

11 months ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

 r=mvqB

rα=mαvqαB

rP=mPvqPB

rαrP=mαqPmPqα=mαmP (qPqα)

=4mm (q2q)=2:1

New answer posted

11 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

In reducing action, H2O2 changes to O2 because it will oxides but option (A) is in acidic medium, hence answer will be (C).

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Since, volume remain constant

64*43πr3=43πR3

R3 = r3 * 64

R = 4r

σbiggerσsmalldrop=5*64*4π24πR2*5=64 (rR)2=64 (r4r)2=6416=4:1

New answer posted

11 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

KCN is used as depressant for ZnS. While Au and Ag, cyanide process (leaching) is used.

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