Class 12th
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11 months agoNew answer posted
11 months agoContributor-Level 10
So, z lies on perpendicular bisector of (0, 1) and (0, 5) i.e., line y = 2 as |z| = 2 z = 2i x = 0 and y = 2 so, x + 2y + 4 = 0
New answer posted
11 months agoContributor-Level 10
Remaining volume of solution = 400 ml
Mass of HNO3 = 25.2 – 11.5 = 13.7
Molarity = = 0.54 M = 54 * 10-2 M
New answer posted
11 months agoContributor-Level 10
At wr impedance of the circuit is equal to the resistance of the circuit.
Left of wr, circuit is mainly capacitive
Right of wr, the circuit is mainly Inductive.
New answer posted
11 months agoContributor-Level 10
Let a and b be the roots of the equation
Therefore a + b = a – 3, ab = 1 – 2a Þ a2 + b2 = (a – 3)2 – 2 (1 – 2a) = a2 – 6a + 9 – 2 + 4a = a2 – 2a + 7 = (a – 1)2 + 6 Þ So,
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