Class 12th

Get insights from 11.9k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th

Follow Ask Question
11.9k

Questions

0

Discussions

49

Active Users

0

Followers

New question posted

11 months ago

0 Follower 1 View

New answer posted

11 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

A'BA=[111][92102112122132142152162172][111]=

[92+122152102+132+162112142+172][111]

=[92+122152102+132+162+112142+172]=[539]

New answer posted

11 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

 t1/2α [Reactant]t=0 (1n),  where n = order of reaction.

New answer posted

11 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Fe3O4 + 8H+ + 8e -> 3Fe + 4H2O

New answer posted

11 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

 |zi|=|z+5i| So, z lies on perpendicular bisector of (0, 1) and (0, 5) i.e., line y = 2 as |z| = 2 z = 2i x = 0 and y = 2 so, x + 2y + 4 = 0

New answer posted

11 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

K e q = ( 1 2 * 1 0 1 5 ) 1 / 2 = 2 . 2 4 * 1 0 ? 8

New answer posted

11 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

Remaining volume of solution = 400 ml

Mass of HNO3 = 25.2 – 11.5 = 13.7

Molarity =  (13.7/63) (400/1000) = 0.54 M = 54 * 10-2 M

New answer posted

11 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

At wr impedance of the circuit is equal to the resistance of the circuit.

Left of wr, circuit is mainly capacitive

 Right of wr, the circuit is mainly Inductive.

New answer posted

11 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Let a and b be the roots of the equation  x 2 + ( 3 a ) x + 1 = 2 a

Therefore a + b = a – 3, ab = 1 – 2a Þ a2 + b2 = (a – 3)2 – 2 (1 – 2a) = a2 – 6a + 9 – 2 + 4a = a2 – 2a + 7 = (a – 1)2 + 6 Þ So,   α 2 + β 2 6

New answer posted

11 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

 C (s)+O2 (g)CO2 (g)Δng=0

qC=20*2=40kJ

Number of moles of C = 2.412=0.2moles

ΔHC=40kJ0.2mole=200kJ/mole

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 703k Reviews
  • 1850k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.