Class 12th

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New answer posted

a year ago

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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a year ago

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V
Vishal Baghel

Contributor-Level 10

  [Co (H2O)6]Cl2⇒Co2+⇒3d7⇒t2g5eg2

Number of unpaired electrons = 3

[Cr (H2O)6]Cl3⇒Cr3+⇒3d3⇒t2g3eg0

Number of unpaired electrons = 3

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

a = F m = m v m = 1 * 1 0 2 = 5 m / s e c 2

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a year ago

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New answer posted

a year ago

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alok kumar singh

Contributor-Level 10

A'BA=[1    1    1][92−102112122132−142−152162172][111]=

[92+122−152−102+132+162    112−142+172][111]

=[92+122−152−102+132+162+112−142+172]=[539]

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Vishal Baghel

Contributor-Level 10

 t1/2α [Reactant]t=0 (1−n),  where n = order of reaction.

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Vishal Baghel

Contributor-Level 10

Fe3O4 + 8H+ + 8e -> 3Fe + 4H2O

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A
alok kumar singh

Contributor-Level 10

 |z−i|=|z+5i| So, z lies on perpendicular bisector of (0, 1) and (0, 5) i.e., line y = 2 as |z| = 2 z = 2i x = 0 and y = 2 so, x + 2y + 4 = 0

New answer posted

a year ago

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Vishal Baghel

Contributor-Level 10

K e q = ( 1 2 * 1 0 1 5 ) 1 / 2 = 2 . 2 4 * 1 0 ? 8

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a year ago

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V
Vishal Baghel

Contributor-Level 10

Remaining volume of solution = 400 ml

Mass of HNO3 = 25.2 – 11.5 = 13.7

Molarity =  (13.7/63) (400/1000) = 0.54 M = 54 * 10-2 M

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