Class 12th

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New answer posted

a year ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 tan? +5tan2? tan? =5? tan2?

tan3? =5

? =n? 3+? 3tan? =5

Five solution.

New answer posted

a year ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 6312+10 (1311+2310+2239+2338+....+2103)

6312=10311 (611−16−1)

=212.1m.n=12

New answer posted

a year ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

 y2=−x2

y=mx−18m

This tangent pass through (2, 0)

m=±14i.e.,   one  tangent  is  x−4y−2=0, 17r=9

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 1+ (1+249) (249−1)=298

M = 1, n = 98

M + n = 99

New answer posted

a year ago

0 Follower 15 Views

V
Vishal Baghel

Contributor-Level 10

Ellipse is x24+y24=1e=12S≡ (0, −2)

Chord of contact is

x2+ (22−2)y4=1

P≡ (1, 2)Q≡2, 0

∴ (SP)2+ (SQ)2=13

New answer posted

a year ago

0 Follower 13 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

a year ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

a year ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Let

P : Ramesh listens to music

Q : Ramesh is out of his village

R : It is Sunday

S : It is Saturday

Then the statement “Ramesh listens to music only if he is in his village and it is Sunday or Saturday can be expressed as

P≡ Ramesh listens to music

∼q≡ He is in village.

r∨s≡ Saturday or Sunday

P⇒ ( (∼q)∧ (r∨s))

New answer posted

a year ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

 P (A/B)=17⇒P (A∩B)P (B)=17

⇒P (B)=79

P (B/A)=25⇒P (A∩B)P (A)=25

⇒P (A)=518

Now,  P (A'∪B)=1−P (A∪B)+P (B)

Both (S1 ) and (S2 ) are true

New answer posted

a year ago

0 Follower 11 Views

V
Vishal Baghel

Contributor-Level 10

 OPOA=tan15°

⇒OA=OPcot15°

OPOC=tan45°⇒OP=OC

Now, OP = OA2−82

OP2= (OP)2cot215°−64

⇒OP=323 (2−3)

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