Class 12th

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New answer posted

a year ago

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Payal Gupta

Contributor-Level 10

Let the spring is in extension state and   a B > a A , a → A B = − a A i ^ − ( − a B i ^ ) = ( − a A + a B ) i ^  

Hence we can say that block moves away from block B in the frame of B

F – kx = MaB           . (1)

kx = Ma                  . (2)

⇒ a B = F M − a

New answer posted

a year ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

r^−i^=2cosθn^...... (1)

i^.n^=−cosθ...... (2)

⇒r^=i^−2 (i^.n^)n^

⇒b→=a→−2 (a→.c→)c→

New answer posted

a year ago

0 Follower 53 Views

P
Payal Gupta

Contributor-Level 10

N=mgcos30°+qEsin30°

a=mgsinθ−qEcosθ−μNm=2.30m/s2

S=ut+12at2

⇒t=2la=1.31sec

New answer posted

a year ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

Frequency increases on filing. So, initial frequency of A is 335 Hz.

f = 340 – 5 = 335 Hz

New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

Z=R2+ (XL−XC)2

Z= (120)2+ (10−100)2=150Ω

ω=1LC=110−1*10−4=105

? ω=2πf

⇒f=1032π10=50Hz

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

A=A0e−λt1  [Radio active decay law]

A5=A0e−λ (t2−t1)

⇒ln5=λ (t2−t1)

⇒Average  life=1λ= (t2−t1)ln5

New answer posted

a year ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Stress = Y * strain

T1A=Y*− (l1−l)l (i)

T2A=Y* (l2−l)l    (ii)

⇒ T1T2=l1−ll2−l

⇒l=T1l2−T2l2T1−T2=T2l1−T1l2T2−T1

New question posted

a year ago

0 Follower 1 View

New answer posted

a year ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

 y=αx−βx2

⇒dydx=α−2βx=0

⇒x=α2β

ymax=α*α2β−β* (α2β)2=α24β

Range = 2x=αβ=2u2sinθ.cosθg

On comparing with

y = x tan θ- gx22u2cos2θ

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

mg – T = ma. (1)

T * R = l α. (2)

a = α R. (3)

With the help of equations (1), (2) and (3), we get

a=mgm+lR2

v=2ah=ωR

⇒ω2=2mghl+mR2

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