Class 12th

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New answer posted

11 months ago

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A
alok kumar singh

Contributor-Level 10

PT=XAPA0-PB0+PB0

ATQ

550=14PA0-PB0+PB0

2200=PA0-PB0+4PB0

560=15PA0-PB0+PB0

2200=PA0-PB0+5PB0

PA0+3PB0=2200

PA0±4PB0=2800PB0=600

PA0=400mmHg

 

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

(A) Neoprene is Elastomer

(B) Nylon- (6, 6) is fibre

(C) PVC is thermoplastic

(D) Novolac is thermosetiting plastic.

New answer posted

11 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

 Z=101 belong to actinoids

104 belong to group 4

 

New answer posted

11 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Due to formation of anilinium ioin in acidic medium meta product is also obtained.

New answer posted

11 months ago

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V
Vishal Baghel

Contributor-Level 10

ln (A) and (C) CH3 – group is activating group

ln (B) Br is weakly deactivating group

ln (D) NO2 is strongly deactivating group

Order of reactivity towards nitration.

D < B < E < A < C.

New answer posted

11 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Z=101 belong to actinoids

104 belong to group 4

New answer posted

11 months ago

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V
Vishal Baghel

Contributor-Level 10

 N2+O2? VeryhighTemp2NO

Reaction is endothermic and required very high temperature for comobination

New answer posted

11 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

y+2x=11+77 ……… (i)

2y+x=211+67 ……… (ii)

x+y=11+1337 ……… (iii)

Centre of the circle given by solving (i) & (ii)

as (873, 11+573)

Again 11y3x=5773 is tangent to the circle.

r = | 1 1 ( 1 1 + 5 7 3 ) 8 7 5 7 7 3 1 1 + 9 | = | 1 1 8 7 2 0 |

( 5 h 8 k ) 2 + 5 r 2 = 8 1 6

New answer posted

11 months ago

0 Follower 24 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

11 months ago

0 Follower 15 Views

P
Payal Gupta

Contributor-Level 10

1 < | z 3 + 2 i | < 4

z = a + i b a , b I              

⇒ 1 < (a 3)2 + (b + 2)2 < 16

in equivalent to 1 < 2 + β2 < 16  α = a 3 l               

( ± 2 , 0 ) ( ± 3 , 0 ) , ( 0 , ± 2 ) ( 0 , ± 3 )             β = b + 2 l

Total 40 such points are possible

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