Class 12th

Get insights from 12k questions on Class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Class 12th

Follow Ask Question
12k

Questions

0

Discussions

65

Active Users

0

Followers

New answer posted

6 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

 r=1a+ (r1)d2r=4, 4 (a+d)=?

ar=1 (12)r+dr=1 (r1) (12)r=4

= (12)2k=0k (12)k1

=14.1 (112)2

= 1

a + d = 4

4 (a + d) = 16

New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

(a, 4a, 7). (3, 1, 2b)= 0

3a + 4a – 14b = 0 a – 2b = 0 ……. (i)

(a, 4a, 7) . (b, a, 2) = 0

ab – 4a2 + 14 = 0……… (ii)

(i) & (ii) =>2b2 – 16b2+ 14 = 0

b2=1a=2b=±2

Plane : x – y + z = 0

P (4, 5, 1)

4 + 5 + 1 = 10

New answer posted

6 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

K=QrΔxΔAT

ML2T-2 (L)L2 (θ) (T)M1L1-T-3θ-1

New answer posted

6 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

 x¯=15i=120xi=300

i=120 (xi15)220=9i=120 (xi15)2=180

i=120 (xi+α)2=178*20=3560

4680+2α (300)+20α2=3560

α2+30α+234178=0

= 2, 28

αmax2= (2)2=4

New answer posted

6 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 72 (1+cos2θ)32 (1cos2θ)2cos22θ=2

Put cos 2 θ= t

Equation 2t2– 5t = 0, t (2t – 5) = 0

t=0, 52

cos 20 = 0, 0 < 2 < 4

x1+x2=2 (tan2θ+cot2θ)?

=2 (1+1)+2 (1+1)+2 (1+1)+2 (1+1)=16

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

L=r*mv

(3i^j^)* (3j^+k^)

=9k^+3 (j^)i^

=i^3j^+9k^

|L|==√1+9+81==√91

New answer posted

6 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

f (x)=3 (x22)3+4=81.3 (x22)3

f' (x)=81.3 (x22)3.ln3.3 (x22)2.2x

From graph : P, Q, R

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

xR=120?

xL=? L=100*100*10? 310?

xC=1? c=1100*100*10? 6=100?

z=1202+ (100? 10)2=1202+902

= 150 ?

? 32=16075*t? t=32*75160=15

New answer posted

6 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

S = {1,2, 3, …., n, 2022}

HCF (n, 2022) = 1

2022 = 2 * 1011 ->3 * 337

2022 = 2 * 3 * 337 (prime factorization)

Let n (A) = no members divisible by 2 = 1011

Let n (B) = no members divisible by 3 = 674

Let n (C) = no members divisible by 337 = 6

n (ABC)=n (A)+n (B)+n (C)n (AB)n (BC)n (CA)+n (ABC)

= 1011 + 674 + 6 – 337 – 2 – 3 + 1

= 1350

n (AB)=337

n ( (ABC)')=20221350=672

Prob. =6722022=3361011=112337

New answer posted

6 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

eVs=hv-?

 At Vs=0hv=? ? =6.62*10-341014 [5.5]? =6.62*10-341014 [5.5]eV1.6*10-19

=2.27

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 684k Reviews
  • 1800k Answers

Share Your College Life Experience

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.