Class 12th

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New answer posted

11 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

A (1, 4, 3)

2x + my + nz = 4

M4+7m2+3n2=4

7m + 3n = 16

AM=(1,12,32)

21=m12=n32

m = 1, n = 3

Plane : 2x + y + 3z = 4

cosθ=|6112|2614=7291

AM = |2+4+94|14=714

cosθ=AMABAB=7/147/291=29114=213*72*7=

New answer posted

11 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Using factual data.

New answer posted

11 months ago

0 Follower 23 Views

V
Vishal Baghel

Contributor-Level 10

y – 1 = m(x – 1)

mx – y + 1 – m = 0

|1m|m2+1=417

17(1m)2=16(m2+1)

m2 – 3m + 1 = 0

bx+10y8=0y=23x}(b+203)x=8

x=243b+20,y=163b+20

b = 2(322)(4+32)2

=1282+921=2

b2 = 2

x25+y22=1

2 = 5 (1 – e2)

e2=35

e=

New answer posted

11 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Diode conducts current only in one direction.

New answer posted

11 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

IF =ex

yex=ex1+e2xdx

dt1+t2

= tan-1 (t) + c

limxexy=limxtan1ex+π4=3π4

New answer posted

11 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 0π2dx3+2sinx+cosxPuttanx2=t12sec2x2dx=dt

=012dt2t2+4t+4=01dt (t+1)2+1= [tan1 (t+1)]01=tan12tan11

New answer posted

11 months ago

0 Follower 21 Views

P
Payal Gupta

Contributor-Level 10

From Truth table Y=AB¯ .

New answer posted

11 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 limx0αex+βex+γsinxxsin2x

=limx0αex+βex+γsinxx3

α+β=0, αβ+γ=0, α+β2=0, α6β6γ6=23

β=αγ=2ααβγ=4α+α+2α=4γ=1

α=1, β=1, γ=2

New answer posted

11 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 1(20a)(40a)+1(40a)(60a)+1(60a)(80a)+.....+1(180a)(200a)=1256

LHS = 120(120a140a)+120(140a160a)+...+120(1180a1200a)

=120(120a1200a)=120.180(20a)(200a)

a2220a+40002304=0a2220a+1696=0

a=220±2048=2122

New answer posted

11 months ago

0 Follower 12 Views

V
Vishal Baghel

Contributor-Level 10

 A3*3, B3*3&AB=0

00|A|=0&|B|=0 only .

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