Coordination Compounds
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A coordination compound CrCl3.4H2O precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write structural formula of the compound and name it.
A coordination compound CrCl3.4H2O precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write structural formula of the compound and name it.
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: The solution CrCl3.4H2O molar conductance shows that it contains one positive and one negative ion.
An ion is present outside the complex when silver chloride is treated with silver nitrate chloride. Outside the complex,
Arrange the following complexes in the increasing order of conductivity of their solution: [Co(NH3)3Cl3], [Co(NH3)4Cl2]Cl, [Co(NH3)6]Cl3, [Cr(NH3)5Cl]Cl2
Arrange the following complexes in the increasing order of conductivity of their solution: [Co(NH3)3Cl3], [Co(NH3)4Cl2]Cl, [Co(NH3)6]Cl3, [Cr(NH3)5Cl]Cl2
This is a Short Answer Type Questions as classified in NCERT Exemplar
Ans: Complexes with more number of ions show more conductivity.
[Co (NH3)3Cl3], [Co (NH3)4Cl2] < [Cr (NH3)5Cl]Cl2
Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands?
Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands?
This is a Long Answer Type Questions as classified in NCERT Exemplar
Ans: The octahedral and tetrahedral splitting up of d orbitals is different.
Δt= ( )Δ0
Δt < Δ0
Δt= CFSE in tetrahedral field
Δ0= CFSE in octahedral field
Comparing CFSE with energy=
What is the relationship between observed colour of the complex and the wavelength of light absorbed by the complex?
What is the relationship between observed colour of the complex and the wavelength of light absorbed by the complex?
This is a Long Answer Type Questions as classified in NCERT Exemplar
Ans: When light wavelengths from a specific part of the spectrum are absorbed by a substance, the result is a complimentary colour. When a complex absorbs a wavelength of light, it reflects a complementary colour. If a violent
CoSO4Cl.5NH3 exists in two isomeric forms ‘A’ and ‘B’. Isomer ‘A’ reacts with AgNO3 to give white precipitate but does not react with BaCl2 . Isomer ‘B’ gives white precipitate with BaCl2 but does not react with AgNO3.
Answer the following questions.
(i) Identify ‘A’ and ‘B’ and write their structural formulas.
(ii) Name the type of isomerism involved.
(iii) Give the IUPAC name of ‘A’ and ‘B’.
CoSO4Cl.5NH3 exists in two isomeric forms ‘A’ and ‘B’. Isomer ‘A’ reacts with AgNO3 to give white precipitate but does not react with BaCl2 . Isomer ‘B’ gives white precipitate with BaCl2 but does not react with AgNO3.
Answer the following questions.
(i) Identify ‘A’ and ‘B’ and write their structural formulas.
(ii) Name the type of isomerism involved.
(iii) Give the IUPAC name of ‘A’ and ‘B’.
This is a Long Answer Type Questions as classified in NCERT Exemplar
Ans: (i) 'A' is [Co (NH3)5SO4]Cl
'B' is [Co (NH3)5Cl]SO4
(ii) Type of isomerism is ionisation isomerism
(iii) IUPAC name of isomer 'A' is pentaaminesulphatocobalt (III)chloride
IUPAC name of isomer 'B' is pentaaminechlorocobalt
Using valence bond theory, explain the following in relation to the complexes given below:
[Mn(CN)6]3- ,[Co(NH3)6]3+ ,[Cr(H2O)6]3+ ,[FeCl]4-
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value
Using valence bond theory, explain the following in relation to the complexes given below:
[Mn(CN)6]3- ,[Co(NH3)6]3+ ,[Cr(H2O)6]3+ ,[FeCl]4-
(i) Type of hybridisation.
(ii) Inner or outer orbital complex.
(iii) Magnetic behaviour.
(iv) Spin only magnetic moment value
This is a Long Answer Type Questions as classified in NCERT Exemplar
Ans:
[Mn (CN)6]3−
Electronic configuration is Mn3+= [Ar]3 d4 hence box electronic structure

(i) Type of hybridisation d2sp3
(ii) Inner orbital complex
(iii) paramagnetic, due to presence of three unpaired electrons.
(iv) S
Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following:
(i) [CoF6]3- ,[Co(H2O)6]2+ ,[Co(CN)6]3-
(ii) [FeF6]3- ,[Fe(H2O)6]2 + ,[Fe(CN)6]4 -
Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following:
(i) [CoF6]3- ,[Co(H2O)6]2+ ,[Co(CN)6]3-
(ii) [FeF6]3- ,[Fe(H2O)6]2 + ,[Fe(CN)6]4 -
This is a Long Answer Type Questions as classified in NCERT Exemplar
Ans: (i) Electronic cnfiguration: Co3+ =[Ar]3d6
Energy level diagram:

Magnetic moment:
Number of unpaired electrons (n)=4
Magnetic moment = μ= =
= = 4.9 BM&nb
9.34 Write down the IUPAC name for each of the following complexes and indicate the oxidation state, electronic configuration and coordination number. Also give stereochemistry and magnetic moment of the complex:
9.34 Write down the IUPAC name for each of the following complexes and indicate the oxidation state, electronic configuration and coordination number. Also give stereochemistry and magnetic moment of the complex:
The complex is an anion with chromium as central atom, 2 water molecules and 2 oxolate ions with -2 negative charge Balance overall charge as 0, we get oxidation state of Cr as:
X + 2 (0) + 2 (-2) = -1 X = + 3.
Name of compound: potassium diaquadioxolatochromate (III) trihydrate. Electronic configura
9.33 Give the oxidation state, d orbital occupation and coordination number of the central metal ion in the following complexes:
(i) K3[Co(C2O4)3]
(ii) cis-[CrCl2(en)2]Cl
(iii) (NH4)2[CoF4]
(iv) [Mn(H2O)6]SO4
9.33 Give the oxidation state, d orbital occupation and coordination number of the central metal ion in the following complexes:
(i) K3[Co(C2O4)3]
(ii) cis-[CrCl2(en)2]Cl
(iii) (NH4)2[CoF4]
(iv) [Mn(H2O)6]SO4
(i) Overall charge balance:
X + 3 (-2) = -3 X = + 3
Oxidation state of Co is + 3.
As there are 3 oxolate ion and being bidentate, coordination no. Of complex is 6. So it is octahedral complex.
d orbital occupation: t2g6eg0 (oxolate ion is weak field ligand, does not cause pairing of electron as the ene
9.32 Discuss the nature of bonding in metal carbonyls.
9.32 Discuss the nature of bonding in metal carbonyls.
Compounds containing carbonyl
Ligands only are known as homoleptic carbonyl. Such types of compounds are formed by most of the transition metals. These metal carbonyls always have simple, well-defined structures. In metal carbonyls the metal - carbonyl bond possess both s and p.character. M-C-bond is