Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine: Overview, Questions, Preparation

Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine 2025 ( Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine )

Vishal Baghel
Updated on Jul 11, 2025 11:32 IST

By Vishal Baghel, Executive Content Operations

Table of content
  • Coordination Compounds Questions and Answers
  • JEE Main Solutions 2022
Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine Logo

Coordination Compounds Questions and Answers

1. Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following: 

(i) [CoF6]3- ,[Co(H2O)6]2+ ,[Co(CN)6]3-

This is a Long Answer Type Questions  as classified in NCERT Exemplar

Ans: Electronic cnfiguration: Co3+ =[Ar]3d6

Energy level diagram:

Magnetic moment:

Number of unpaired electrons (n)=4

Magnetic moment =   μ= n ( n + 2   =  4 ( 4 + 2

   =  24   = 4.9 BM 

[Co(H2O)6]2+

Electronic cnfiguration: Co2+=[Ar]3 d7

Energy level diagram:

Magnetic moment: Since ,number of unpaired electrons (n)=3, therefore magnetic moment = 3 ( 3 + 2 = 15 = 3.87BM

 

[Co(CN)6]3−

Electronic configuration: [Ar]Co3+=3 d6

Energy level diagram:

(ii) [FeF6]3- ,[Fe(H2O)6]2 + ,[Fe(CN)6]4 -

Ans: [FeF6]3−

Electronic configuration: Fe3+=[Ar]3 d5

Energy level diagram:

Number of unpaired electrons =  μ= n ( n + 2 = 5 ( 5 + 2 =  μ= 35 = 5.95BM [Fe(H2O)6]2+

Fe2+=[Ar]3 d6

Energy level diagram:

Magnetic moment

Since, number of unpaired electrons (n)=4, therefore magnetic moment is-

4 ( 4 + 2 = 24 = 4.9BM

[Fe(CN)6]4−

Electronic configuration: Fe2+=[Ar]3 d6

Energy level diagram

Since CNis strong field ligand, it forces all the electrons to get paired up Magnetic moment.

In the absence of unpaired electrons it behaves as diamagnetic ( ie. no magnetic behaviour ).

So magnetic moment = zero

2. Using valence bond theory, explain the following in relation to the complexes given below: 

[Mn(CN)6]3- ,[Co(NH3)6]3+ ,[Cr(H2O)6]3+ ,[FeCl]4- 

(i) Type of hybridisation. 

(ii) Inner or outer orbital complex. 

(iii) Magnetic behaviour. 

(iv) Spin only magnetic moment value

This is a Long Answer Type Questions  as classified in NCERT Exemplar

Ans:

[Mn(CN)6]3−

Electronic configuration is Mn3+=[Ar]3 d4 hence box electronic structure

(i) Type of hybridisation d2sp3

(ii) Inner orbital complex

(iii) paramagnetic, due to presence of three unpaired electrons.

(iv) Spin only magnetic moment is calculated using the formula : n=2 in this case, we get spin only magnetic moment in BMas = 2 ( 2 + 2 = 8  = 2.87BM

 

[Co(NH3)6]3+

Electronic configuration of Co3+=[Ar]3 d6

(i) Hyb As shown in the above box electronic structure the type of hybridisation is ........... d2sp3

(ii) Inner orbital complex

(iii) Diamagnetic

(iv) Zero( Since no unpaired electrons are present, as depicted above)

 

[Cr(H2O)6]3+

(i) type of hybridisation........ d2sp3

(ii) Inner orbital complex

(iii) paramagnetic

(iv) 3.87BM

[Fe(Cl)6]4−

electronic configuration is of Fe2+=[Ar]3 d6

(i) type of hybridisation will be sp3d2

(ii) Outer orbital complex

(iii) Paramagnetic

(iv) 4.9BM

3. CoSO4Cl.5NH3 exists in two isomeric forms ‘A’ and ‘B’. Isomer ‘A’ reacts with AgNO3 to give white precipitate but does not react with BaCl2 . Isomer ‘B’ gives white precipitate with BaCl2 but does not react with AgNO3

Answer the following questions. 

(i) Identify ‘A’ and ‘B’ and write their structural formulas.

This is a Long Answer Type Questions  as classified in NCERT Exemplar

Ans: ‘A’ is [Co(NH3)5SO4]Cl

‘B’ is [Co(NH3)5Cl]SO4

(ii) Name the type of isomerism involved.
Ans: Type of isomerism is ionisation isomerism
(iii) Give the IUPAC name of ‘A’ and ‘B’.  

Ans: IUPAC name of isomer ‘A’ is pentaaminesulphatocobalt(III)chloride

IUPAC name of isomer ‘B’ is pentaaminechlorocobalt(III)sulphate

4. What is the relationship between observed colour of the complex and the wavelength of light absorbed by the complex?

This is a Long Answer Type Questions  as classified in NCERT Exemplar

Ans: When light wavelengths from a specific part of the spectrum are absorbed by a substance, the result is a complimentary colour. When a complex absorbs a wavelength of light, it reflects a complementary colour. If a violent colour is absorbed, for example, yellow is conveyed. The CFSE value, often known as the colour definer for any complex, comes next. To determine the wavelength value in order to determine which colour absorbs the most energy.

Δe= h c λ

As λ has shorter wavelength.

Low spin complexes absorb shorter wavelengths, while high spin complexes absorb longer ones. The colour theory, complex, and wavelength are all determined using this method.

 

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Commonly asked questions
Q:  

Using crystal field theory, draw energy level diagram, write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following: 

(i) [CoF6]3- ,[Co(H2O)6]2+ ,[Co(CN)6]3-

(ii) [FeF6]3- ,[Fe(H2O)6]2 + ,[Fe(CN)6]4 -

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Q:  

Using valence bond theory, explain the following in relation to the complexes given below: 

[Mn(CN)6]3- ,[Co(NH3)6]3+ ,[Cr(H2O)6]3+ ,[FeCl]4- 

(i) Type of hybridisation. 

(ii) Inner or outer orbital complex. 

(iii) Magnetic behaviour. 

(iv) Spin only magnetic moment value

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Q:  

CoSO4Cl.5NH3 exists in two isomeric forms ‘A’ and ‘B’. Isomer ‘A’ reacts with AgNO3 to give white precipitate but does not react with BaCl2 . Isomer ‘B’ gives white precipitate with BaCl2 but does not react with AgNO3

Answer the following questions. 

(i) Identify ‘A’ and ‘B’ and write their structural formulas.

(ii) Name the type of isomerism involved.

(iii) Give the IUPAC name of ‘A’ and ‘B’.  

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Q:  

What is the relationship between observed colour of the complex and the wavelength of light absorbed by the complex?

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Q:  

Why are different colours observed in octahedral and tetrahedral complexes for the same metal and same ligands?

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Q:  

Arrange the following complexes in the increasing order of conductivity of their solution: [Co(NH3)3Cl3], [Co(NH3)4Cl2]Cl, [Co(NH3)6]Cl3, [Cr(NH3)5Cl]Cl2

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Q:  

A coordination compound CrCl3.4H2O precipitates silver chloride when treated with silver nitrate. The molar conductance of its solution corresponds to a total of two ions. Write structural formula of the compound and name it.

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Q:  

A complex of the type [M(AA)2X2]n +  is known to be optically active. What does this indicate about the structure of the complex? Give one example of such a complex.

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Q:  

Magnetic moment of [MnCl4]2- is 5.92 BM. Explain giving reason.

Q:  

Based on crystal field theory explain why Co(III) forms a paramagnetic octahedral complex with weak field ligands whereas it forms a diamagnetic octahedral complex with strong field ligands.

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Q:  

Why are low spin tetrahedral complexes not formed?

Q:  

Give the electronic configuration of the following complexes based on Crystal Field Splitting theory [CoF6]3-,[Fe(CN)6]4-and [Cu(NH3)6]2+ 

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Q:  

Explain why [Fe(H2O)6]3+ has magnetic moment value of 5.92 BM whereas [Fe(CN)6]3- has a value of only 1.74 BM. 

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Q:  

Arrange following complex ions in increasing order of crystal field splitting energy (Δ0)

[Cr(Cl)6]3- ,[Cr(CN)6]3- ,[Cr(NH3)6]3+ 

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Q:  

Why do compounds having similar geometry have different magnetic moments?

Q:  

CuSO4.5H2O is blue in colour while CuSO4 is colourless. Why?

Q:  

Name the type of isomerism when ambidentate ligands are attached to central metal ion. Give two examples of ambidentate ligands.

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Q:  

Which of the following complexes formed by Cu2+ ions are most stable?

(i) Cu2+ + 4NH3⇌[Cu(NH3)4]2+,log⁡K=11.6

(ii) Cu2+ + 4CN−⇌[Cu(CN)4]2−,log⁡K=27.3

(iii) Cu2+ + 2en⇌[Cu(en)2]2+,log⁡K=15.4

(iv) Cu2+ + 4H2O⇌[Cu(H2O)4]2+,log⁡K=8.9

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Q:  

The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes,  [Co(NH3)6]3+,  [Co(H2O)6]3+.

A: [Co(H2O)6]3+ > [Co(NH3)6]3+ > [Co(H2O)6]3+ .

B: [Co(NH3)6]3+ > [Co(H2O)6]3+ > [Co(CN)6]3- 

C: [Co(H2O)6]3+ >  [Co(NH3)6]3+ > [Co(CN)6]3- 

D: [Co(CN)6]3- >  [Co(NH3)6]3+ >  [Co(H2O)6]3+

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Q:  

When 0.1 mol CoCl3(NH3)5 is treated with excess of AgNO3, 0.2 mol of AgCl are obtained. The conductivity of solution will correspond to

A: 1:3 electrolyte

B: 1:2 electrolyte

C: 1:1 electrolyte

D: 3:1 electrolyte

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Q:  

When 1 mol [CrCl3(H2O)3]6H2O is treated with excess of AgNO3, 3 mol of AgCl are obtained. The formula of the complex is: 

A: [CrCl3(H2O)3 ].3H2O

B: [CrCl2(H2O)4]Cl.2H2O

C: [CrCl2(H2O)5]Cl2H2O

D: [Cr(H2O)6]Cl3

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Q:  

The correct IUPAC name of [Pt(NH3)2Cl2] is

(i) Diamminedichloridoplatinum (II)

(ii) Diamminedichloridoplatinum (IV)

(iii) Diamminedichloridoplatinum (0)

(iv) Dichloridodiammineplatinum (IV)

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Q:  
The stabilisation of coordination compounds due to chelation is called the chelate effect. Which of the following is the most stable complex species? 

A: [Fe(CO)5]

B: [Fe(CN)6]3- 

C: [Fe(C2O4)3]3- 

D: [Fe(H2O)6]3+ 

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Q:  

Indicate the complex ion which shows geometrical isomerism.

A: [Cr(H2O)4Cl2]+ 

B: [Pt(NH3)3Cl]

C: [Co(NH3)6]3+ 

D: [Co(CN)5](NC)3- 

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Q:  

The CFSE for octahedral [CoCl6]4- is 18,000 cm−1. The CFSE for tetrahedral [CoCl4]2- will be

A: 18,000 cm−1

B: 16,000 cm−1

C: 8,000 cm−1

D: 20,000 cm−1

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Q:  

Due to the presence of ambidentate ligands coordination compounds show isomerism. Palladium complexes of the type [Pd(C6H5)2(SCN)2] and [Pd(C6H5)2(NCS)2] are

(A) Linkage isomers

(B) Coordination isomers

(C) Ionization isomers

(D) Geometrical isomers

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Q:  

The compounds [Co(SO4)(NH3)5] Brand [Co(SO4)(NH3)5]Cl represent

A: Linkage isomerism 

B: Ionisation isomerism 

C: Coordination isomerism

D: No isomerism

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Q:  

A chelating agent has two or more than two donor atoms to bind to a single metal ion. Which of the following is not a chelating agent?

A: Thiosulphato 

B: Oxalato 

C Glycinato

D: Ethane-1,2-diamine

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Q:  

Which of the following species is not expected to be a ligand?

A: NO

B: NH4+ 

C: NH2CH2CH2NH2

D: CO

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Q:  

What kind of isomerism exists between [Cr(H2O)6]Cl3 (violet) and [Cr(H2O)5Cl]Cl2H2O (greyish-green)?

A: Linkage isomerism

B: Solvate isomerism

C: Ionisation isomerism 

D: Coordination isomerism

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Q:  

IUPAC name of [Pt(NH3)2Cl(NO2)] is 

A: Platinum diaminechloronitrite

B: Chloronitrito-N-ammineplatinum (II)

C Diamminechloridonitrito-N-platinum (II) 

D Diamminechloronitrito-N-platinate (II)

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Q:  

Atomic numbers of Mn, Fe, and Co are 25, 26 and 27 respectively. Which of the following inner orbital octahedral complex ions are diamagnetic?

A: [Co(NH3)6]3+ 

B: [Mn(CN)6]3- 

C: [Fe(CN)6]4- 

D: [Fe(CN)6]3- 

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Q:  

Atomic number of Mn, Fe, Co and Ni are 25, 26 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons?

A: [MnCl6]3- 

B: [FeF6]3- 

C: [CoF6]3- 

D: [Ni(NH3)6]2+

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Q:  

Which of the following options are correct for [Fe(CN)6]3 -  complex?

A: d2sp3 hybridisation 

B: sp3d2 hybridisation

C: Paramagnetic 

D: Diamagnetic

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Q:  

An aqueous pink solution of cobalt (II) chloride changes to deep blue on addition of excess of HCl. This is because____________.

A: [Co(H2O)]2+ is transformed into [CoCl6]4- 

B: [Co(H2O)6]2+ is transformed into [CoCl4]2- 

C: Tetrahedral complexes have smaller crystal field splitting than octahedral complexes. 

D: Tetrahedral complexes have larger crystal field splitting than octahedral complex.

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Q:  

Which of the following complexes are homoleptic?

A: [Co(NH3)6]3+ 

B: [Co(NH3)4]+ 

C: 4[Ni(CN)4]2- 

D: [Ni(NH3)4Cl2]

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Q:  

Which of the following complexes are heteroleptic?

A: [Cr(NH3)6]3+ 

B: [Fe(NH3)4Cl]+ 

C: [Mn(CN)6]4- 

D: [Co(NH3)6Cl2]

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Q:  

Identify the optically active compounds from the following.

A: [Co(en)3]3+  

B: trans - [Co(en)2]+  

C: cis - [Co(en)2Cl2]+ 

D: [Cr(NH3)5Cl] 

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Q:  

Identify the correct statements for the behaviour of ethane-1, 2-diamine as a ligand.

A: It is a neutral ligand. 

B: It is a didentate ligand.

C: It is a chelating ligand. 

D: It is a unidentate ligand

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Q:  

Which of the following complexes show linkage isomerism?

A: [Co(NH3)5(NO2)]2+ 

B: [Co(H2O)5]3+ 

C: [Cr(NH3)5SCN]2+ 

D: [Fe(en)5Cl2]+

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Q:  

Match the complex ions given in Column I with the colours given in Column II and assign the correct code

Column I (Complex ion)

Column II (Colour)

A. [Co(NH3)6]3+ 

1. Violet

B. [Ti(H2O)6]3+ 

2. Green

C. [Ni(H2O)6]2+ 

3. Pale blue

D. [Ni(H2O)4(en]2+ (aq)

4. Yellowish orange

 

5. Blue

 

Code

(i) A (1)           B (2)          C (4)           D (5)

(ii) A (4)          B (3)          C (2)           D (1)

(iii) A (3)         B (2)          C (4)           D (1)

(iv) A (4)         B (1)          C (2)           D (3)

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Q:  

Match the coordination compounds given in Column I with the central metal atoms given in Column II and assign the correct code

Column I (Coordination Compound)

Column II (Central metal atom)

A. Chlorophyll

1. Rhodium

B. Blood pigment

2. Cobalt

C. Wilkinson catalyst

3. calcium

D. Vitamin B12

4. iron

 

5. magnesium

Code

(i)   A (5)     B (4)     C (1)     D (2)

(ii)  A (3)     B (4)     C (5)     D (1)

(iii) A (4)     B (3)     C (2)     D (1)

(iv) A (3)     B (4)     C (1)     D (2)

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Q:  

Match the complex ions given in Column I with the hybridisation and number of unpaired electrons given in Column II and assign the correct code

Column I (Complex ion)

Column II (Hybrisization, number of unpaired electrons)

A. [Cr(H2O)6]3+ 

1. dsp2, 1

B. [Co(CN)4]2- 

2. sp3d2, 5

C. [Ni(NH3)6]2+ 

3. d2sp3, 3

D. [MnF6]4- 

4. sp3, 4

 

5. sp3d2, 2

Code

 (i) A (3)     B (1)      C (5)      D (2)

(ii) A (4)     B (3)      C (2)      D (1)

(iii) A (3)    B (2)      C (4)      D (1) 

(iv) A (4)     B (1)     C (2)     D (3)

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Q:  

Match the complex species given in Column I with the possible isomerism given in Column II and assign the correct code

Column I (Complex species)

Column II (Isomerism)

A. [Co(NH3)4Cl2]+ 

1. Optical

B. cis - [Co(en)2Cl2]+ 

2. Ionisation

C. [Co(NH3)5(NO2)]Cl2

3. Coordination

D. [Co(NH3)6][Cr(CN)6]

4. geometrical

 

5. linkage

Code :

(i)  A (1)     B (2)     C (4)     D (5) 

(ii) A (4)      B (3)     C (2)     D (1) 

(iii) A (4)     B (1)     C (5)     D (3) 

(iv) A (4)     B (1)     C (2)     D (3)

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Q:  

Match the compounds given in Column I with the oxidation state of cobalt present in it (given in Column II) and assign the correct code.

Column I (Compound)

Column II (Oxidation state of Co)

A. [Co(NCS)(NH3)5(SO3)]

1. + 4

B. [Co(NH3)4Cl2]SO4

2. 0

C. Na4[Co(S2O3)3]

3. +1

D. [Co2(CO)8]

4. +2

 

5. +3

Code 

(i) A (1)     B (2)      C (4)      D (5)

(ii) A (4)    B (3)      C (2)      D (1) 

(iii) A (5)   B (1)      C (4)      D (2) 

(iv) A (4)   B (1)      C (2)      D (3)

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Q:  

In the following questions a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.

A: Assertion and reason both are true, reason is correct  of assertion. 

B: Assertion and reason both are true, but reason is not the correct  of assertion.

C: Assertion is true, reason is false.

D: Assertion is false, reason is true

1. Assertion: Toxic metal ions are removed by the chelating ligands. 

    Reason: Chelate complexes tend to be more stable.

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Q:  

Assertion : [Cr(H2O)6]Cl2 and [Fe(H2O)6]Cl2 are reducing in nature. 

 Reason: Unpaired electrons are present in their d-orbitals.

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Q:  

Assertion: Linkage isomerism arises in coordination compounds containing ambidentate ligand.                      

Reason: Ambidentate ligand has two different donor atoms.

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Q:  

Assertion: Complexes of MX6 and MX5L type (X and L are unidentate) do not show geometrical   isomerism.

Reason: Geometrical isomerism is not shown by complexes of coordination number 6.

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Q:  

Assertion: [Fe(CN)6]3- ion shows magnetic moment corresponding to two unpaired electrons.       

Reason: Because it has d2sp3 type hybridisation.

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Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine Logo

JEE Main Solutions 2022

JEE Mains Solution 2022

Q&A Icon
Commonly asked questions
Q:  

Which of the following pair of molecules contain odd electron molecule and an expanded octet molecule?

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Q:  

  N 2 ( g ) + 3 H 2 ( g ) ? 2 N H 3 ( g )

20g     5g

Consider the above reaction, the limiting reagent of the reaction and number of moles of NH3 formed respectively are:

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Q:  

100 mL of 5% (w/v) solution of NaCl in water was prepared in 250 mL beaker. Albumin from the egg was poured into NaCl solution and stirred well. This resulted in a/an:

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Q:  

The first ionization enthalpy on Na, Mg and Si, respectively, are : 496, 737 and 786 kJ mol-1. The first ionization enthalpy (kJ mol-1) of Al is:

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Q:  

In metallurgy the term “gangue” is used for:

Q:  

The reaction of zinc with excess of aqueous alkali, evolves hydrogen gas and gives:

Q:  

Lithium nitrate and sodium nitrate, when heated separately, respectively, give:

Q:  

Number of lone pairs of electrons in the central atom of SCl2, O3, ClF3 and SF6, respectively are:

Q:  

In following pairs, the one in which both transition metal ions are colourless is:

Q:  

In neutral of faintly alkaline medium KMnO4 being a powerful oxidant can oxidize, thiosulphate almost quantitatively, to sulphate. In this reaction overall change in oxidation state of manganese will be:

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Q:  

Which among the following pairs has only herbicides?

Q:  

Which among the following is the strongest Bronsted base?

Q:  

Which of the following compounds is an example of hypnotic drug?

Q:  

Resistance of a conductivity cell (cell constant 129 m1) filled with 74.5 ppm solution of KCl is 100Ω (labeled as solution 1). When the same cell is filled with KCl solution of 149 ppm, the resistance is 50Ω (labeled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e. 12=x×103. The value of x is________. (Nearest integer)

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Q:  

Ionic radii of cation A+ and anion B are 102 and 181 pm respectively. These ions are allowed to crystallize into an ionic solid. This crystal has cubic close packing for B. A+ is present in all octahedral voids. The edge length of the unit cell of the crystal AB is________ pm.

(Nearest integer)

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Q:  

The minimum uncertainty in the speed of an electron in an one dimensional region of length 2a0 (Where a0 = Bohr radius 52.9 pm) is__________ km s-1.

(Given: Mass of electron = 9.1 × 10-31 kg, Planck’s constant h = 6.63 × 10-34 Js)

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Q:  

When 600 mL of 0.2 M HNO3 is mixed with 400 mL of 0.1 M NaOH solution in a flask, the rise in temperature of the flask is_________ × 10-2 °C.

(Enthalpy of neutralization = 57 kJ mol-1 and Specific heat of water = 4.2 JK-1 g-1)

(Neglect heat capacity of flask)

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Q:  

If O2 gas is bubbled  through water at 303 K, the number of millimoles of O2 gas that dissolve in 1 litre of water is______________. (Nearest integer)

(Given: Henry’s Law constant for O2 at 303 K is 46.82 k bar and partial pressure of O2 = 0.920 bar)

(Assume solubility of O2 in water in too small, nearly negligible)

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Q:  

If the solubility product of PbS is 8 × 10-28, then the solubility of PbS in pure water at 298 K is x × 1 0 1 6 m o l L 1 .  The value of x is__________. (Nearest integer)

[Given: 2 = 1 . 4 1 ]  

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Q:  

The reaction between X and Y is first order respect to X and zero order with respect to Y.

Examine the data of table and calculate ratio of numerical values of M and L (Nearest integer)

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Q:  

In a linear tetrapeptide (Constituted with different amino acids), (number of amino acids) (number of peptide bonds) is_______________.

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Q:  

In bromination of Propyne, with Bromine 1, 1, 2, 2-tetrabromopropane is obtained in 27% yield. The amount of 1, 1, 2, 2- tetrabromopropane obtained from 1g of Bromine in this reaction is_______________× 10-1g. (Nearest integer) (Molar mass: Bromine = 80g / mol)

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Q:  

 [Fe(CN)6]3 should be an inner orbital complex. Ignoring the pairing energy, the value of crystal field stabilization energy for this complex is (-) _________ Δ0. (Nearest integer)

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Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine Exam

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