Haloalkanes and Haloarenes

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a month ago

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A
alok kumar singh

Contributor-Level 10

This is the formation of free radical mechanism, hence free radical will be formed

 

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Organic compound → AgBr (s)

  0.5 g                    0.40 g

Here; Moles of Br in organic compound = Moles of Br in Ag Br

= Moles of AgBr

0 . 4 0 1 8 8 m o l

Mass of Br in organic compound =  0 . 4 1 8 8 * 8 0 g  

% o f B r = 0 . 4 * 8 0 1 8 8 * 0 . 5 * 1 0 0 % = 3 4 %

New answer posted

a month ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

kindly consider the following Image 

 

New answer posted

a month ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

kindly consider the following Image 

 

New answer posted

a month ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

kindly consider the following Image 

 

New answer posted

a month ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

kindly consider the following Image 

 

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

With AlCl3, alkyl halide will form cabocation which will show rearrangement.

 

New answer posted

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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V
Vishal Baghel

Contributor-Level 10

[ Z n ( g l y ) 2 ] is optically active compound

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V
Vishal Baghel

Contributor-Level 10

Addition on triple bond takes place by the addition of hydrogen

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