Haloalkanes and Haloarenes

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New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Above reaction is S?1 reaction as it proceed via formation of carbocation. Polar solvent is more suitable for S?1 and racemisation takes place.

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

E2 elimination. Most acidic proton is removed. Fluorine is more electronegative.

 

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Reaction (1) is SN1 (rate independent of [OH? ]). Reaction (2) is E2 (rate depends on [OH? ]).
Statement (B) is correct. Changing concentration of base will have no effect on reaction (1).

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Reaction path is SN2 because OH? is strong nucleophile, but hydroxyl ion will not attack on chiral centres and so there is retension of configuration.

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

Δng=-1/2. Kp=Kc (RT)? ¹/². Kc=Kp (RT)¹/².

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Is bulky base, so elimination is dominating.

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