JEE Main

If you see now for 2019, only IPU CET forms are available. Besides JEE, other are state level exam form COMEDK JAMIA.

First of all Jadavpur University accept the admission on the basis of WBJEE. So, you have to qualify the WBJEE by getting approximate 120 out of 200 marks according to the latest cut off. For more information you can hit the link:
https://www.shiksha.com/university/jadavpur-university-faculty-of-engineering-and-technology-ju-Kolkata-19992/courses

NIT-Trichy and NIT-Warangal are the best options for metallurgical and materials engineering.

Check out the links below for JEE Mains rank and college prediction:
https://www.shiksha.com/b-tech/resources/jee-main-rank-predictor
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor

Hello Yatender Kumar,
Firstly, your question appears to be of theoretical nature because National Testing Agency has not yet announced its results and without that, no student can know his all India rank. 0k, be that as it may, but let me tell you that it is simply impossible to calculate the OBC rank based on the All India Rank because there is no mathematical relation between these two. I would strongly advise you to wait for a few days since National Testing Agency is expected to announce the date for the result in a day or two which is expected to be before the end of this month.

No, with this score, you cannot get admission.

It depends upon the cut-off that university releases. However, you might get a seat. Your chances are good.

I guess, you can get admission with this score. Hope this helps you. Be free to share any problem you have. All the best for your bright future.

In most of the colleges, the minimum eligibility criteria is 45% aggregate or 50% Aggregate. So, seeing your score, it's quite difficult to get hassle free admission. I hope this helps you. Be free to share any problem you have.
All the best for your bright future!