Kinetic Theory

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New answer posted•a year ago

Kinetic Theory Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen

At a certain temperature, the degrees of freedom per molecule for gas is 8. The gas performs 150 J at work when it expands under constant pressure. The amount of heat absorbed by the gas will be________J.

4 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

Degree of freedom, f = 8

$∴ C_{V} = \frac{8}{2} R = 4 R a n d C_{P} = 4 R + R = 5 R$

So, H = $Δ U + W$

at constant pressure, W = $P Δ v$

150 = $n R Δ T$

So, $H = n C_{V} Δ T = n 5 R Δ T = 5 (n R Δ T)$

= 5 × 150

= 750 J

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New answer posted•a year ago

Kinetic Theory Physics NCERT Exemplar Solutions Class 12th Chapter Eleven

A vessel contains 14 g of nitrogen gas at a temperature of 27°C. The amount of heat to be transferred to the gas to double the r.m.s speed of its molecules will be:

Take R = 8.32 J mole1 k1.

3 Views|Posted a year ago

Asked by Vishal Baghel

Answered by

Vishal Baghel | Contributor-Level 10

a year ago

$m_{N_{2}} = 14 g, T = 27 ° C = 300 k$

To double the Vrms Tf = 4Ti = 4 × 300 = 1200 k.

$∴ Q = n C_{v} Δ T$

$= 5 \times 225 R = 1125 R = 1125 \times 3.32$

= 9360 J.

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New answer posted•a year ago

Kinetic Theory Physics NCERT Exemplar Solutions Class 12th Chapter Thirteen

According to kinetic theory of gases,

A. The motion of the gas molecules freezes at 0°C.

B. The mean free path of gas molecules decreases if the density of molecules is increased.

C. The mean free path of gas molecules increases if temperature is increased keeping pressure constant.

D. Average kinetic energy per molecules per degree of freedom is  $\frac{3}{2} k_{B} T$ (for monoatomic gases).

Choose the most appropriate answer form the options given below

4 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

$\bar{x}$ (mean free path) = $\frac{1}{\sqrt[]{2} π d^{2} n_{v}}$

$n_{v} = \frac{n N_{A}}{v},$ n → No. of moles in volume v N_A ® Avogadro’s Number

$\frac{n}{v} = \frac{P}{R_{T}}$

$\bar{x} \propto v \propto \frac{1}{ρ (d e n s i t y} & \bar{x} α T a t c o n s t a n t P)$

^{$ρ ↑ \Leftrightarrow \bar{x} ↓ | \bar{x} ↑ \Leftrightarrow T ↑$}

The motion of the gas molecules freezes at 0K not 0° C

Average kinetic Energy per molecule

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New answer posted•a year ago

Kinetic Theory Physics NCERT Exemplar Solutions Class 11th Chapter Thirteen

When an ideal gas is compressed adiabatically, its temperature rises: the molecules on the average have more kinetic energy than before. The kinetic energy increases

(a) Because of collisions with moving parts of the wall only

(b) Because of collisions with the entire wall

(c) Because the molecules gets accelerated in their motion inside the volume

(d) Because of redistribution of energy amongst the molecules

7 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is a multiple choice answer as classified in NCERT Exemplar

When the gas is compressed adiabatically, the total work done on the gas increases its internal energy which in turn increases the KE of the gas molecule and hence, the collisions between molecules also increases.

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New answer posted•a year ago

Kinetic Theory Physics NCERT Exemplar Solutions Class 11th Chapter Thirteen

Which of the following diagrams (Fig.) depicts ideal gas behaviour?

8 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is a multiple choice answer as classified in NCERT Exemplar

(a), (c) pV=nRT

(a) when pressure p =constant

volume is directly proportional to temperature

(b) when T= constant

from PV =constant

so the graph is rectangular hyperbola

from pressure is directly proportional to temper

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New answer posted•a year ago

Kinetic Theory Physics NCERT Exemplar Solutions Class 11th Chapter Thirteen

In a diatomic molecule, the rotational energy at a given temperature

(a) Obeys Maxwell’s distribution

(b) Have the same value for all molecules

(c) Equals the translational kinetic energy for each molecule

(d) Is (2/3)rd the translational kinetic energy for each molecule

5 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is a multiple choice answer as classified in NCERT Exemplar

(a), (d) The total energy associated with the molecule is

E= $\frac{1}{2} m v_{x}^{2} + \frac{1}{2} m v_{y}^{2} + \frac{1}{2} m v_{z}^{2} + \frac{1}{2} I_{x} w_{x}^{2} + \frac{1}{2} I_{y} w_{y}^{2}$

The number of independent terms in the above expressions is 5. So we can predict velocities of molecule by maxwell’s distribution, hence the above expression obeys maxwell ‘s

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New answer posted•a year ago

Kinetic Theory Physics NCERT Exemplar Solutions Class 11th Chapter Thirteen

Diatomic molecules like hydrogen have energies due to both translational as well as rotational motion. From the equation in kinetic theory pV =2/3 E , E is

(a) The total energy per unit volume

(b) Only the translational part of energy because rotational energy is very small compared to the translational energy

(c) Only the translational part of the energy because during collisions with the wall pressure relates to change in linear momentum

(d) The translational part of the energy because rotational energies of molecules can be of either sign and its average over all the molecules is zero

9 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is a multiple choice answer as classified in NCERT Exemplar

(c) According to kinetic theory, we know walls only exert perpendicular forces on molecule. They do not exert parallel force . so there is only change in translational motion.

So pV=2/3E

Where E is representing only translational part of

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New answer posted•a year ago

Kinetic Theory Physics NCERT Exemplar Solutions Class 11th Chapter Thirteen

ABCDEFGH is a hollow cube made of an insulator (Fig). Face ABCD has positive charge on it. Inside the cube, we have ionized hydrogen. The usual kinetic theory expression for pressure

(a) Will be valid.

(b) Will not be valid since the ions would experience forces other than due to collisions with the walls.

(c) Will not be valid since collisions with walls would not be elastic.

(d) Will not be valid because isotropy is lost.

7 Views|Posted a year ago

Asked by Payal Gupta

Answered by

Payal Gupta | Contributor-Level 10

a year ago

This is a multiple choice answer as classified in NCERT Exemplar

(b), (d) due to the presence of external positive charge on face ABCD. The usual expression for pressure on the basis of kinetic energy will not be valid as ions would also experience electrostatic force. So presence of positive charge

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New answer posted•a year ago

Kinetic Theory Physics NCERT Exemplar Solutions Class 11th Chapter Thirteen