Kinetic Theory

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New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

V_rms = √ (3RT/M)
V_N? = V_H?
√ (3RT_N? / M_N? ) = √ (3RT_H? / M_H? )
573/28 = T_H? /2
⇒ T_H? = 40.928

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

τ 1 T

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

λ = kT / (√2πd²P)
= (1.38*10? ²³ * 300) / (√2 * 3.14 * (0.3*10? )² * 1.01*10? )
≈ 102 nm

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

1 litre, T = 300K, P = 2 atm, KE = 2*10? J/molecule, no of molecule =?
No. of molecules = (no of moles) * NA = nNA
Also, n = PV/RT = PV/ (NAkT)
KE = (3/2)kT = 2*10? J [Given]
kT = (4/3)*10?
P = 2 atm = 2 * 1.013 * 10? N/m²
vol = 1 lit = 10? ³ m³
No. of molecules = PV/kT = (2*1.013*10? * 10? ³)/ (4/3)*10? ) ≈ 1.5 * 10¹¹

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

T = 2 7 ° C , P = 1 a t m = 1 0 5 N / m 2 , V r m s = 2 0 0 m / s

As we know

v r m s = 3 R T M v r m s v ' r m s = 3 R T M 3 R T ' M

V ' r m s = 2 0 0 * 2 3 = x 3

x = 400

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

According to KTG, the gas exerts pressure because its molecule :

suffer change in momentum when impinge on the walls of container.

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

Δ U + Δ K E = 0

f 2 n R Δ T = 1 2 m v 2 Δ T = m n v 2 f R = 4 * 1 0 3 * 3 0 2 3 R = 3 . 6 3 R K .

New answer posted

a month ago

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P
Payal Gupta

Contributor-Level 10

Translational kinetic energy will be equal to rotational kinetic energy corresponds to each degree of freedom.

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a month ago

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A
alok kumar singh

Contributor-Level 10

At same temperature, curve with higher volume corresponds to lower pressure.

V 3 > V 2 > V 1

P 1 > P 2 > P 3

(We draw a straight line parallel to volume axis to get this)

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

K.E. energy of electron = eV

Translational K.E. of N2 =   3 2 K T

So eV = 3 2 K T  

1 . 6 * 1 0 1 9 * 0 . 1 = 3 2 * 1 . 3 8 * 1 0 2 3 * T                

T = 773 – 273 = 500°C

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