Kinetic Theory
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New answer posted
a month agoContributor-Level 10
V_rms = √ (3RT/M)
V_N? = V_H?
√ (3RT_N? / M_N? ) = √ (3RT_H? / M_H? )
573/28 = T_H? /2
⇒ T_H? = 40.928
New answer posted
a month agoContributor-Level 10
λ = kT / (√2πd²P)
= (1.38*10? ²³ * 300) / (√2 * 3.14 * (0.3*10? )² * 1.01*10? )
≈ 102 nm
New answer posted
a month agoContributor-Level 10
1 litre, T = 300K, P = 2 atm, KE = 2*10? J/molecule, no of molecule =?
No. of molecules = (no of moles) * NA = nNA
Also, n = PV/RT = PV/ (NAkT)
KE = (3/2)kT = 2*10? J [Given]
kT = (4/3)*10?
P = 2 atm = 2 * 1.013 * 10? N/m²
vol = 1 lit = 10? ³ m³
No. of molecules = PV/kT = (2*1.013*10? * 10? ³)/ (4/3)*10? ) ≈ 1.5 * 10¹¹
New answer posted
a month agoContributor-Level 10
According to KTG, the gas exerts pressure because its molecule :
suffer change in momentum when impinge on the walls of container.
New answer posted
a month agoContributor-Level 10
Translational kinetic energy will be equal to rotational kinetic energy corresponds to each degree of freedom.
New answer posted
a month agoContributor-Level 10
At same temperature, curve with higher volume corresponds to lower pressure.
(We draw a straight line parallel to volume axis to get this)
New answer posted
a month agoContributor-Level 10
K.E. energy of electron = eV
Translational K.E. of N2 =
So eV =
T = 773 – 273 = 500°C
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