Kinetic Theory

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New answer posted•a year ago
S
a year ago

This is a long answer type question as classified in NCERT Exemplar

Consider the diagram

let n =number of molecules per unit volume

Vrms= rms speed of gas molecule

When block is moving with speed vo, relative speed of molecules w.r.t front face =v+vo

Coming head on, momentum transferred to block per coll

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New answer posted•a year ago
S
a year ago

This is a long answer type question as classified in NCERT Exemplar

Given volume V = 1m3

area = 0.01mm2

= 8.01 × 10 - 6 m2= 10 - 8 m2

Temperature both inside and outside are equal

So initial pressure inside the box = 1.50atm

Final pressure inside the box= 0.1atm

Assuming Vx= speed of nitrogen molecule in x direction

ni

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New answer posted•a year ago
S
a year ago

This is a long answer type question as classified in NCERT Exemplar

Time require to avoid the collision T= l/v where l = mean free path =1/ 2 π d 2 n

Where n = N/V

n=number of aeroplanes/volume

= 10 20 × 20 × 1.5 = 0.0167 k m -3

T= 1 V 2 π d 2 N × 1 v

T= 1 2 × 3.14 × 20 2 × 0.0167 × 10 - 6 × 150 = 10 6 1776.25 × 2.505

= 10 6 4449.5 = 224.74 h ≈ 225 h

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

This is a long answer type question as classified in NCERT Exemplar

(a) The moon has small gravitational force and hence, the escape velocity is small .

As the moon in the proximity of the earth as seen from the sun, the moonhas the same amount of heat per unit area as that of the earth.

The air molec

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

13.12 Rate of diffusion of hydrogen, R1= 28.7 cm3 s–1

Rate of diffusion of another gas, R2 = 7.2 cm3 s–1

According to Graham's law of diffusion, we have:

 R1R2= M2M1, where M1= molecular mass of hydrogen = 2.02 g and M2 is the molecular mass of the unknown gas

M2=M1* (R1R2)2= 2.02* (28.77.2)2= 32.09 = Molecular mass of Oxygen

Henc

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New answer posted•a year ago
S
a year ago

13.11 Length of the narrow bore, L = 1 m = 100 cm

Length of the mercury thread, l = 76 cm

Length of the air column between mercury and the closed end, lo  = 15 cm

Since the bore is held vertically in air with the open end at the bottom, the mercury length that occupies the air space is 100 – (7

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New answer posted•a year ago
S
a year ago

13.10 Pressure inside the cylinder containing nitrogen, P = 2.0 atm = 2 ×1.013×105 Pa

Temperature inside the cylinder, T = 17 ?=290K

Radius of nitrogen molecule, r = 1.0 Å = 1 ×10-10 m

Diameter of nitrogen molecule, d = 2 ×10-10 m

Molecular mass of nitrogen molecule, M = 28 u = 28 g (assume)

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