Mathematical Reasoning

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

p →~ (p ∧ ~ q)
=~ p ∨ ~ (p ∧ ~ q)
=~ p ∨ ~ p ∨ q
=~ p ∨ q

New answer posted

5 months ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

5 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Let p denotes statement
p: I reach the station in time.
q: I will catch the train.
Contrapositive of p→q is q→p
q→p: I will not catch the train, then I do not reach the station in time.

New answer posted

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

(p⇒q)∧ (q⇒¬p) ≡ (¬p∨q)∧ (¬q∨¬p) ≡ ¬p∧ (q∨¬q) ≡ ¬p.

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

If A ⊆ B and B ⊆ D then A ⊆ C
Contrapositive is
If A ⊄ C, then A ⊄ B or B ⊄ D

New answer posted

5 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

5 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Truth table analysis shows that (P ∨ Q) ∧ (¬P) is equivalent to Q ∧ ¬P.
Then (Q ∧ ¬P) ⇒ Q. This is a tautology.
The provided solution seems to have an error.
Let's check the options. (P ∨ Q) is a tautology. (P ∧ ¬Q) is a contradiction.
~ (P ⇒ Q) ⇔ P ∧ ¬Q is true.

New answer posted

5 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

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A -> B

 

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(A -> B) -> B is a tautology

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