Tags Mathematical Reasoning

Mathematical Reasoning

Get insights from 119 questions on Mathematical Reasoning, answered by students, alumni, and experts. You may also ask and answer any question you like about Mathematical Reasoning

Follow Ask Question

119

Questions

Discussions

Active Users

Followers

New answer posted

3 months ago

Mathematical Reasoning Maths NCERT Exemplar Solutions Class 11th Chapter Fourteen

The negation of the statement “72 is divisible by 2 and 3” is

(a) 72 is not divisible by 2 or 72 is not divisible by 3.

(b) 72 is not divisible by 2 and 72 is not divisible by 3.

(c) 72 is divisible by 2 and 72 is not divisible by 3.

(d) 72 is not divisible by 2 and 72 is divisible by 3.

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} L e t p : 72 i s d i v i s i b l e b y 2 a n d 3 . \\ a n d q : 72 i s d i v i s i b l e b y 2 . \\ r : 72 i s d i v i s i b l e b y 3 . \\ ∴ \sim q : 72 i s n o t d i v i s i b l e b y 2 . \\ \sim r : 72 i s n o t d i v i s i b l e b y 3 . \\ S o, \sim (q \land r) : \sim q \lor \sim r \\ \Rightarrow 72 i s n o t d i v i s i b l e b y 2 o r 72 i s n o t d i v i s i b l e b y 3 . \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

0 0

New answer posted

3 months ago

Mathematical Reasoning Maths NCERT Exemplar Solutions Class 11th Chapter Fourteen

The negation of the statement “7 is greater than 8” is

(a) 7 is equal to 8.

(b) 7 is not greater than 8.

(c) 8 is less than 7.

(d) none of these

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} L e t p : 7 i s g r e a t e r t h a n 8 . \\ \sim p : 7 i s n o t g r e a t e r t h a n 8 . \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

0 0

New answer posted

3 months ago

Mathematical Reasoning Maths NCERT Exemplar Solutions Class 11th Chapter Fourteen

The negation of the statement “A circle is an ellipse” is

(a) An ellipse is a circle.

(b) An ellipse is not a circle.

(c) A circle is not an ellipse.

(d) A circle is an ellipse.

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} L e t p : A c i r c l e i s a n e l l i p s e . \\ \sim p : A c i r c l e i s n o t a n e l l i p s e . \\ H e n c e, t h e c o r r e c t o p t i o n i s (c) . \end{array}$

0 0

New answer posted

3 months ago

Mathematical Reasoning Maths NCERT Exemplar Solutions Class 11th Chapter Fourteen

The connective in the statement “Earth revolves round the Sun and Moon is a satellite of earth” is

(a) or

(b) Earth

(c) Sun

(d) and

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} C o n n e c t i v e w o r d i s " a n d " . \\ H e n c e, t h e c o r r e c t o p t i o n i s (d) . \end{array}$

0 0

New answer posted

3 months ago

Mathematical Reasoning Maths NCERT Exemplar Solutions Class 11th Chapter Fourteen

The connective in the statement

“2 + 7 > 9 or 2 + 7 < 9 is

(a) and

(b) Or

(c) >

(d) <

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} I n' 2 + 7 > 9 o r 2 + 7 < 9' t h e c o n n e c t i v e i s' o r' . \\ H e n c e, t h e c o r r e c t o p t i o n i s (b) . \end{array}$

0 0

New answer posted

3 months ago

Mathematical Reasoning Maths NCERT Exemplar Solutions Class 11th Chapter Fourteen

Which of the following is not a statement

(a) Smoking is injurious to health.

(b) 2 + 2 = 4

(c) 2 is the only even prime number.

(d) Come here.

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} T o g i v e o r d e r c a n n o t b e a s t a t e m e n t . \\ S o,' C o m e h e r e' i s n o t a s t a t e m e n t . \\ H e n c e, t h e c o r r e c t o p t i o n i s (d) . \end{array}$

0 0

New answer posted

3 months ago

Mathematical Reasoning Maths NCERT Exemplar Solutions Class 11th Chapter Fourteen

Which of the following is a statement.

(a) x is a real number.

(b) Switch off the fan.

(c) 6 is a natural number.

(d) Let me go.

0 Follower 2 Views

Payal Gupta

Contributor-Level 10

This is an Objective Type Questions as classified in NCERT Exemplar

$\begin{array}{l} Since s t a t e m e n t i s a s e n t e n c e w h i c h i s e i t h e r t r u e o r f a l s e . \\ S o, 6 i s a n a t u r a l n u m b e r w h i c h i s t r u e . \\ H e n c e, t h e c o r r e c t o p t i o n i s (c) . \end{array}$

0 0

New answer posted

3 months ago

Mathematical Reasoning Maths NCERT Exemplar Solutions Class 11th Chapter Fourteen

Using the contrapositive method, prove that if $n^{2}$ is an even integer, then $n$ is also an even integer.

0 Follower 3 Views

Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l} L e t p : n^{2} i s a n e v e ninteger . \\ q : n i s a l s o a n e v e n integer . \\ A l s o l e t \sim q i s t r u e i . e ., n i s n o t a n e v e n integer . \\ \Rightarrow n^{2} i s n o t a n e v e n integer . \\ \Rightarrow \sim p i s t r u e . [? S q u a r e o f a n o d d integer i s o d d] \\ H e n c e, \sim q i s t r u e \Rightarrow \sim p i s t r u e . \end{array}$

0 0

New answer posted

3 months ago

Mathematical Reasoning Maths NCERT Exemplar Solutions Class 11th Chapter Fourteen

Prove by the direct method that for any real numbers $x, y$ , if $x = y$ , then $x^{2} = y^{2}$ .

0 Follower 3 Views

Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l} L e t p : x = y, x, y \in R \\ O n s q u a r i n g b o t h s i d e s w e h a v e \\ x^{2} = y^{2} : q (s a y) \\ \Rightarrow p = q H e n c e, p r o v e d . \end{array}$

0 0

New answer posted

3 months ago

Mathematical Reasoning Maths NCERT Exemplar Solutions Class 11th Chapter Fourteen

Prove the following statement by the contradiction method:

$p$ : The sum of an irrational number and a rational number is irrational.

0 Follower 3 Views

Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

$\begin{array}{l} L e t p i s f a l s e i . e ., t h e s u m o f a n i r r a t i o n a l n u m b e r a n d a r a t i o n a l n u m b e r i s r a t i o n a l . \\ L e t \sqrt[]{λ} i s i r r a t i o n a l a n d n i s r a t i o n a l n u m b e r \\ \Rightarrow \sqrt[]{λ} + n = r (r a t i o n a l) \\ \Rightarrow \sqrt[]{λ} = r - n \\ W e o b s e r v e t h a t \sqrt[]{λ} i s i r r a t i o n a l w h e r e a s (r - n) i s r a t i o n a l w h i c h i s a c o n t r a d i c t i o n . \\ S o, o u r supposition i s w r o n g . \\ H e n c e, p i s t r u e . \end{array}$

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
687k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Mathematical Reasoning

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience