Maths

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New answer posted

10 months ago

0 Follower 13 Views

P
Payal Gupta

Contributor-Level 10

B = (I – adjA)5

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New answer posted

10 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

|z|=3 circle with radius = 3

arg  (z1z+1)=π4,  part of a circle (with radius 2 ). no common points

New answer posted

10 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

x4 + x2 + 1 = 0

x4 + 2x2 + 1 – x2 = 0

(x2+1+x) (x2x+1)=0

x=±ω, ? ω2

Now, = α1011+α2022α3033

ω1011+ω2022ω3033

= 1 + 1 – 1 = 1

New question posted

10 months ago

0 Follower 7 Views

New answer posted

10 months ago

0 Follower 10 Views

P
Payal Gupta

Contributor-Level 10

 dydx=11+sin2x

dy=sec2xdx (1+tanx)2

y=11+tanx+c

When

x=π4, y=12 gives c = 1

So

x+π4=5π6or13π6x=7π12or23π12

sum of all solutions =

π+7π12+23π12=42π12

Hence k = 42

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