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New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Let

P : Ramesh listens to music

Q : Ramesh is out of his village

R : It is Sunday

S : It is Saturday

Then the statement “Ramesh listens to music only if he is in his village and it is Sunday or Saturday can be expressed as

P Ramesh listens to music

q He is in village.

rs Saturday or Sunday

P ( (q) (rs))

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 P (A/B)=17P (AB)P (B)=17

P (B)=79

P (B/A)=25P (AB)P (A)=25

P (A)=518

Now,  P (A'B)=1P (AB)+P (B)

Both (S1 ) and (S2 ) are true

New answer posted

4 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 OPOA=tan15°

OA=OPcot15°

OPOC=tan45°OP=OC

Now, OP = OA282

OP2= (OP)2cot215°64

OP=323 (23)

New answer posted

4 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

For angle to the acute U.V>0

a (logeb)212+6a (logeb)>0

b>1

Let loge b = t > 0 as b > 1

Y = at2 + 6at – 12 & y > 0  t > 0

a?

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Normal of plane P : = |i^j^k^213122|=4i^j3k^

Equation of plane P which passes through (2, 2) is 4x – y – 3z – 12 = 0

Now, A (3, 0, 0), B (0, 12 0), C (0, 4)

α=3, β12, γ=4P=α+β+γ=13

Now, volume of tetrahedron OABC

V=|16OA. (OB*OC)|=24

(V, P) = (24, 13)

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Given,  L1:x1λ=y21=z32

and L2:x+262=y+183=z+28λ

are coplanar

|272031λ1223λ|=0

λ=3

Now, normal of plane P, which contains L1 and L2

equation of required plane P : 3x + 13y – 11z + 4 = 0

(0, 4, 5) does not lie on plane P.

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

H : x 2 a 2 y 2 b 2 = 1

Foci : S (ae, 0), S' (ae, 0)

Focus of parabola is (ae, 0)

Now, semi latus rectum of parabola = |SS'| = 2ae

Given, 4ae=e (2b2a)

B2 = 2a2……… (i)

Given, (22, 22) lies on H

1a21b2=18........ (ii)

From (i) and (ii)

a2=4, b2=8

? b2=a2 (e21)

e=3

equation of parabola is  y2 =83x

New answer posted

4 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

C : (x – 2)2 + y2 = 1

Equation of chord AB : 2x = 3

OA=OB=3

AM=32

AreaofΔOAB=12 (2AM) (OM)

=334sq.unit

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Equation of circle passing through (0, 2) and (0, 2) is

x2+ (y24)+λx=0, (λR)

Divided by x we get

x2+ (y24)x+λ=0

Differentiating w.r.t. x

x [2x+2y.dydx] [x2+y24].1x2=0

2xy.dydx+ (x2y2+4)=0

New answer posted

4 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 dydx+1x21y= (x1x+1)1/2

dydx+py=Q

I.F=ePdx= (x1x+)12

x2loge|x+1|+C

Curves passes through  (2, 13)

C=2loge353

atx=8, 7y (8)=196loge3

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