Maths

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New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

 l=600π2 (sin6xsin4xsinx+sin4xsin2xsinx+sin2xsinx)dx

l=600π2 (2cos5x+2cos3x+2cosx)dx

l=60 (25sin5x+23sin3x+2sinx)|0π/2 = 104

New answer posted

4 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

X  0 1 2 3

P (X) 16 12 310 130

σ2=Σx2P (x) (Σ*P (x)2=56100)

100σ2=56

New answer posted

4 months ago

0 Follower 18 Views

V
Vishal Baghel

Contributor-Level 10

 |z2|=|z¯|.21|z||z|=1

z2=z¯z3=1

z=worw2

wn= (1+w)n= (w2)n

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

 tan? +5tan2? tan? =5? tan2?

tan3? =5

? =n? 3+? 3tan? =5

Five solution.

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

 6312+10 (1311+2310+2239+2338+....+2103)

6312=10311 (611161)

=212.1m.n=12

New answer posted

4 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

 y2=x2

y=mx18m

This tangent pass through (2, 0)

m=±14i.e., onetangentisx4y2=0, 17r=9

New answer posted

4 months ago

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V
Vishal Baghel

Contributor-Level 10

 1+ (1+249) (2491)=298

M = 1, n = 98

M + n = 99

New answer posted

4 months ago

0 Follower 8 Views

V
Vishal Baghel

Contributor-Level 10

Ellipse is x24+y24=1e=12S (0, 2)

Chord of contact is

x2+ (222)y4=1

P (1, 2)Q2, 0

(SP)2+ (SQ)2=13

New answer posted

4 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

4 months ago

0 Follower 6 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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