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New question posted
2 months agoNew answer posted
2 months agoContributor-Level 10
lim? →? (1/3 (a+2x)? ²/³2 - 1/3 (3x)? ²/³3) / (1/3 (3a+x)? ²/³1 - 1/3 (4x)? ²/³4)
= (1/3 (3a)? ²/³ (2-3) / (1/3 (4a)? ²/³ (1-4) = (3? ²/³)/ (4? ²/³) * 1/3
= (2? /³)/ (9¹/³) * 1/3 * 2/3 (1/9)¹/³
New answer posted
2 months agoContributor-Level 10
f' (x) = k*x (x+1) (x-1) = k (x³-x)
=> f (x) = k (x? /4 - x²/2) + C
=> f (0) = C
=> f (x) = f (0)
=> k (x? -2x²)/4 + C = C
=> x² (x²-2)=0
=> x = {0, √2, -√2}
New question posted
2 months ago
New answer posted
2 months agoContributor-Level 10
T? =? C? (3x²/2)? (-1/3x)?
=? C? (3/2)? (-1/3)? x¹? ³? for the term independent of x put r = 6
=> T? =? C? (3/2)³ (-1/3)?
=? C? (1/6)³ = (9x8x7)/ (3x2x1) (1/6)³ = 7/18
New answer posted
2 months agoContributor-Level 10
S.D. = √ (∑? ¹? (x? -p)²/10) - (∑? ¹? (x? -p)/10)²
√9/10 - (3/10)² = √9/10 - 9/100
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