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Moving Charges and Magnetism

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4 months ago

Moving Charges and Magnetism Physics NCERT Exemplar Solutions Class 12th Chapter Four

Three vectors A, B and C add up to zero. Find which is false.

(a) (A×B) × C is not zero unless B, C are parallel

(b) (A×B).C is not zero unless B, C are parallel

(c) If A,B,C define a plane, (A×B)×C is in that plane

(d) (A×B).C=|ABC|→ C2=A2+B2

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4 months ago

Moving Charges and Magnetism Physics NCERT Exemplar Solutions Class 12th Chapter Four

In a two dimensional motion, instantaneous speed v0 is a positive constant. Then which of the following are necessarily true?

(a) The acceleration of the particle is zero.

(b) The acceleration of the particle is bounded.

(c) The acceleration of the particle is necessarily in the plane of motion.

(d) The particle must be undergoing a uniform circular motion.

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer-b, d

Explanation- as given motion is two-dimensional motion and given that instantaneous speed v_o is positive constant. Acceleration is rate of change of velocity. hence it will also be in the plane of motion.

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4 months ago

Moving Charges and Magnetism Physics NCERT Exemplar Solutions Class 12th Chapter Four

In a two dimensional motion, instantaneous speed v₀ is a positive constant. Then which of the following are necessarily true?

(a) The average velocity is not zero at any time.

(b) Average acceleration must always vanish.

(c) Displacements in equal time intervals are equal.

(d) Equal path lengths are traversed in equal intervals.

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- d

Explanation – speed = total distance travelled /time taken

Total distance travelled = path length

= speed $*$ time

We should be very careful with the fact, that speed is related with total distance covered not with displacement.

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4 months ago

Moving Charges and Magnetism Physics NCERT Exemplar Solutions Class 12th Chapter Four

Consider the quantities, pressure, power, energy, impulse, gravitational potential, electrical charge, temperature, area. Out of these, the only vector quantities are

(a) Impulse, pressure and area

(b) Impulse and area

(c) Area and gravitational potential

(d) Impulse and pressure

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation – we know that impulse J= f. $? t$ = $? p$ , where F is force . $? t$ is time duration and $? p$ is change in momentum. As $? p$ is a vector quantity, hence impulse is also a vector quantity. Sometimes area can also be treated as vector.

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4 months ago

Moving Charges and Magnetism Physics NCERT Exemplar Solutions Class 12th Chapter Four

The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be

(a) 60 m

(b) 71 m

(c) 100 m

(d) 141 m

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- c

Explanation - we know that $θ$ =15⁰ and R= 50m

Range, R= $\frac{u^{2} s i n 2 θ}{g}$

50 = $\frac{u^{2} s i n 2 * 15}{g}$

So u²= 980

So u = $\sqrt[]{980} = 7 * 2 * \sqrt[]{5}$ m/s

So u= 14 $* 2.23$ = 31.304m/s

$θ$ = 45⁰, R= $\frac{u^{2} s i n 2 (45)}{9.8} = \frac{u^{2}}{g}$

R= $\frac{({14 \sqrt[]{5)}}^{2}}{g}$ = $\frac{14 * 14 * 5}{9.8}$ = $100 m$

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4 months ago

Moving Charges and Magnetism Physics NCERT Exemplar Solutions Class 12th Chapter Four

The component of a vector r along X-axis will have maximum value if

(a) r is along positive Y-axis

(b) r is along positive X-axis

(c) r makes an angle of 45° with the X-axis

(d) r is along negative Y-axis

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation – ler r makes an angle $?$ with positive x axis component if r along x-axis.

So r_x= |r|cos $?$

(r_x)_maximum= |r| (cos $?$ )_maximum

= |r|cos $0$ = r

$?$ =0⁰

R is along positive x-axis.

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4 months ago

Moving Charges and Magnetism Physics NCERT Exemplar Solutions Class 12th Chapter Four

Shows the orientation of two vectors u and v in the XY plane. If u = aȋ + bĵ and

v=p ȋ + q ĵ . which of the following is correct?

(a) a and p are positive while b and q are negative.

(b) a, p and b are positive while q is negative.

(c) a, q and b are positive while p is negative.

(d) a, b, p and q are all positive.

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation – u= a? + b? as u in the first quadrant, hence both components a and b will be positive. For v= p? + q? , as it is positive x direction and located downward hence x component p will be positive and y component q will be negative.

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4 months ago

Moving Charges and Magnetism Physics NCERT Exemplar Solutions Class 12th Chapter Four

Which one of the following statements is true?

(a) A scalar quantity is the one that is conserved in a process.

(b) A scalar quantity is the one that can never take negative values.

(c) A scalar quantity is the one that does not vary from one point to another in space.

(d) A scalar quantity has the same value for observers with different orientations of the axes.

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- d

Explanation- a scalar quantity is independent of direction hence has the same value for observers with different orientations of the axes.

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4 months ago

Moving Charges and Magnetism Physics NCERT Exemplar Solutions Class 12th Chapter Four

The angle between A= ȋ + ĵ and B = ȋ - ĵ is

(a) 45° (b) 90° (c) –45° (d) 180°

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alok kumar singh

Contributor-Level 10

This is a Multiple Choice Questions as classified in NCERT Exemplar

Answer- b

Explanation-A = i+j

B = i-j

A.B=|A|B|cos $θ$

(? +? ). (? -? ) = $(\sqrt[]{1 + 1}) (\sqrt[]{1 + 1})$ cos $θ$

Where $θ$ is the angle between A and B

Cos $θ$ = $\frac{1 - 0 + 0 - 1}{\sqrt[]{2 \sqrt[]{2}}}$ = $\frac{0}{2} = 0$

$θ$ = 90^o

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4 months ago

Moving Charges and Magnetism Physics NCERT Exemplar Solutions Class 12th Chapter Four

If A = 2 and B = 4, then match the relations in column I with the angle θ between A B and in column II. Column I Column II °

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alok kumar singh

Contributor-Level 10

This is a Short Answer Type Questions as classified in NCERT Exemplar

Explanation- - given |A|=2 and |B|=4

a) |A $* B$ |=AB cos $θ$ = 0

so 2 $* 4$ cos $θ$ =0

so $θ = 90$ so it matches with ii

b) |A $*$ B|= ABcos $θ$ =8

2 $* 4$ cos $θ$ =8

So $θ$ = 0 so it matches with option i

c) |A $*$ B|= ABcos $θ$ =4

so $θ$ =60 so it matches with option iv

d) |A $*$ B|= ABcos $θ$ =-8

so $θ$ =180 so it matches with option iii

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